-MOSFET: IV;l= 2 V, Idss =10 mA, Iş=1.6 mA, rd=14 K, R_=2 K. Calculate the dc drain-to-source voltage. Please write your answer as a V and don't use units in the answer. Please use one digit after the dot. -7 V Is (t Vo RL Vi 5 V 2 V
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D-MOSFET: lVtl= 2 V, Idss =10 mA, Is=1.6 mA, rd=14 K, RL=2 K.
Calculate the dc drain-to-source voltage.
Please write your answer as a V and don’t use units in the answer.
Please use one digit after the dot.
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- a. If you do not go completely around the loop when applying Kirchhoff’s voltage law, then the algebraic sum of the voltages cannot be determined the algebraic sum of the voltages will always be positive the algebraic sum of the voltages will always be negative the algebraic sum is the voltage between the start and finish points b. A p -type semiconductor is a semiconductor doped with impurity atoms whose electron valence is +4 pentavalent impurity atoms trivalent impurity atomsPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to IL-DC =0:5A RL VL-DC =20V 220V omsb O 001 F O 0.02 F O 0.0167F O None of the above ActivatePower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V omsh RL VI-DC20V 0.01 F 0.02 F 0.0167 F None of the above
- A charging circuit that will deliver constant DC current will be designed. The input of the circuit is 220V / 50Hz AC and its outputIt will be 5V / 2A DC.The circuit will consist of 3 parts:AC transformer will reduce the voltage on the inputii. AC rectifier circuit will convert low AC voltage to DCiii. Current source, this part will keep the current at the output constant.You determine the transformer drop rate in the first part. Its output is low voltage ACas the source and design the second and third parts accordingly.Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20VPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to c 20:5A L VI-DC20V 220V omsh T 0.01 F 0.02 F 0.0167 F None of the above euer
- In the circuit shown below. Determine the following a. Vs (at the secondary) b. Vout (across RL) c. Vrip (ripple votage) d. VDC e. PIV (Peak Inverse Voltage) 10:1 Output 115 V mis 60 Hz RL 2.2 k) D, 50μF- All diodes are IN4001. Tund AlMannai EENG261 Page 5/11For the voltage-divider bias network of Figure 1: a. Determine re. b. Calculate Zi and Zo. c. Find Av. d. Repeat parts (b) and (c) with ro = 25 k.A full-wave bridge rectifier is to be designed to produce a peak output voltage of 10 V, deliver 100 mA to the load, and produce an output with a ripple of not more than 7.5 percent. Assume that the frequency of the source is 50 Hz, and that a constant drop voltage model with Vp = 0.7 V is t of used. D1 D2 vs(1) RL vz(?) D3 D4 Source Rectifier Load a) Calculate the needed value of the load resistor R1. 1 b) Calculate the peak value of the voltage source which should be used V (t). [ c) What will be the value of the ripple voltage V7 [ d) Calculate the value of the required capacitor C. [ e) Explain in your own words the difference between the output with and without using the capacitor in the circuit above.
- A half-wave rectifier is needed to supply 15-V dc to a load that draws an average current of 250 mA. The peak-to-peak ripple is required to be 0.2 V or less. What is the minimum value allowed for the smoothing capacitance?multirange ammeter was designed using direct method to give three scales with Rsh1= 0.001285989 0, Rsh2=0.000562552 0, and Rsh3=0.000100001 Q. The d'Arsonval meter has Rm=6 Q and full scale current of 1.5 mA. Find the ranges.? 8 (Ctrl) -5 For the following circuit: a) Draw a table to mention the names, the states (ON/OFF) and turn on voltages for all the diodes of the circuit. (V = 3.5V for D3) and draw the equivalent circuit. b) Find the voltage across R1, R2, R3 c) Find the current through D1 , Dz , D3 and D4 D1 Si R2 D2 5002 Si R1 7502 R3 D3 D4 V1 1kn Blue GaAs 10v