Model Summary Adjusted R Std. Error of the Model R R Square Square Estimate 1 .919 887 64259 ANOVA Model Sum of Squares df Mean Square F Sig 1 Regression 11.718 002 Residual Total 25.500 7 Coefficients Standardized Unstandardized Coefficients Coefficients 4 Model B Std. Error Beta t Sig. 1 (Constant) 83.230 1.574 52.882 000 TVAdv .304 1.153 7.532 001 NewsAdv .321 .621 4.057 010 What is SSE? O.605 1.065 O-2.506 O 2.605

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Chicken diet and weight:  Compare the effects of six types of feed: casein, horsebean, linseed, meat meal, soybean, and sunflower. The ANOVA output below can be used to test for differences between the mean weights of chicks on different diets.   df Sum Sq Mean Sq F value Pr(>F) feed 5 231129.16 46225.83 15.36 0.0000 residuals 65 195556.02 3008.55     If we conducted a hypothesis test to determine if these data provide convincing evidence that the mean weight of chicks varies across some (or all) groups we would find a difference between mean weight of chicks between at least two of the diets using an overall αα = 0.05.   Mean SD n casein 323.58 64.43 12 horsebean 160.2 38.63 10 linseed 218.75 52.24 12 meatmeal 276.91 64.9 11 soybean 246.43 54.13 14 sunflower 328.92 48.84 12 Now use the summary above to test that casein and horsebean have a different effect on mean weights of chicks.Find the alpha level to use for this pairwise comparison to four…

Chicken diet and weight: Compare the effects of six types of feed: casein, horsebean, linseed, meat meal, soybean, and sunflower. The ANOVA output below can be used to test for differences between the mean weights of chicks on different diets. df Sum Sq Mean Sq F value Pr(>F) feed 5 231129.16 46225.83 15.36 0.0000 residuals 65 195556.02 3008.55 If we conducted a hypothesis test to determine if these data provide convincing evidence that the mean weight of chicks varies across some (or all) groups we would find a significant difference between average weight of chicks between at least two of the diets using an overall a = 0.05. Mean SD n casein 323.58 64.43 12 horsebean 160.2 linseed 218.75 38.63 10 52.24 12 meatmeal 276.91 64.9 11 soybean 246.43 54.13 14 sunflower 328.92 48.84 12 Now use the summary above to test that meatmeal and sunflower are significantly different. Fcdf = (Round to three decimal places.) The test statistic for this pairwise comparison is: t = (Round to three…

rse ations Suppose a study was done to determine whether the average amount of sleep that students get the night before an exam is less than 6 hours. An SRS of 100 students from a university was taken, and a mean of 5.5 hours was computed from the sample. The figure below provides the results of the analysis. Normal calculator Density 04 0.3 02 0.1 0 -3 -2 Mean: 0 Std. Dev. 1 Prob(X<= -2.5 )=0.0062096654 Snapshot Close Compute What is your conclusion based on the results of this study? (Assume a significance level of 0.05.) O On average, students typically get less than 6 hours of sleep the night before an exam. O On average, students typically get 6 hours of sleep the night before an exam. O On average, students typically get more than 6 hours of sleep the night before an exam. O On average, students typically get 5.5 hours of sleep the night before an exam.

Wk 5 Exercises [due Day 5] i Refer to the ANOVA table for this regression. Source d.f. 20 45 SS MS Regression Residual 1,192,019 1,602,669 59,601 35,615 Total 2,794,688 65 (a) State the degrees of freedom for the F test for overall significance. The degrees of freedom for regression are 20 and for error 45 (b) Use Appendix F to look up the critical value of Ffor a = .05. (Round your answer to 2 de es 05 (c-1) Calculate the Fstatistic. (Round your answer to 4 decimal places.) F statistic

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Summary of Fit RSquare 0.673175 0.659743 RSquare Adj Root Mean Square Error Mean of Response Observations (or Sum Wgts) 11.36538 106.8831 77 Analysis of Variance Sum of Source DF Squares Mean Square F Ratio Model 3 19422.399 6474.13 50.1203 Error 73 9429.549 129.17 Prob > F C. Total 76 28851.948 |t| Intercept 29.593628 7.186991 4.12 <.0001* Sugars 3.8623817 0.348158 11.09 <.0001* Sodium 0.0089653 0.016746 0.54 0.5940 Carbo 3.3058183 0.408135 8.10 <.0001* 1. Using the above JMP output, which of the predictors present concern to the overall model? Assume the response, y, is calories found in a cup of cereal.

Question Find the area to the right of the z-score -1.90 under the standard normal curve. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -2.1 0.0179 0.0174 0.0170 0.0166 0.0162 0.0158 0.0154 0.0150 0.0146 0.0143 -2.0 0.0228 0.0222 0.0217 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183 -1.9 0.0287 0.0281 0.0274 0.0268 0.0262 0.0256 0.0250 0.0244 0.0239 0.0233 -1.8 0.0359 0.0351 0.0344 0.0336 0.0329 0.0322 0.0314 0.0307 0.0301 0.0294 Use the value(s) from the table above. Provide your answer below: FEEDBACK MORE INSTRUCTION SUBMIT Content attribution