Minimize the state table 2, and show your partitions and your reduced final table. Present State Next State x = 0 Y₂Y₁Yo B D A E G x = 1 Y₂Y1Yo C E F C H B D F Y2Y1Y0 A B C D E F G H Table 2: State Table Question lb Yield H F E 1 0 1 0 1 1 0 1

Create a trigger named InstructorInsertSalaryTR that fires when a new row is added to the Instructors table. Throw an error when multiple rows are inserted. When there is only one row inserted, validate that the AnnualSalary value is positive (strictly greater than zero) and less than or equal to 120000. Throw an error with appropriate message if the salary value is negative or too big. Also, if the salary value is between 0 and 10000, assume that there was a mistake of entering monthly salary instead of annual salary, and multiply the salary value by 12. For example, if the new value of the salary is 5000, it should be changed to 60000. No need to validate any other data from the inserted row. Test the trigger with appropriate INSERT statements. There should be four cases: 1) with negative salary, 2) with positive salary <= 10000, 3) with salary greater that 10000 and less than or equal to 120000, and 4) with salary > 120000.

Don't use AI.

pop_most_recent_value doesn't work correctly for Make sure pop_most_recent_value() works correctly when adding more values than space allows for

Q3/Add the number (100110to 10101) by using 7482IC?

If you are unsure of the location of the update.txt file on your computer, print a copy.

Read in one integer value, which I will call start for this explanation. Ensure that start is between 5 and 100, including those values.  Include proper prompts for both the initial entry and in case of an error. The following loop will execute start number of times; Beginning with the start value entered, decrement the loop_step by 1 down to 1. Do not go to 0. If the current loop iteration value is even, an accumulator variable will be incremented by 1/loop_step. So, if the loop_step was 12, the accumulator variable would be incremented by 1/12. If the current loop iteration value is odd, the accumulator variable will be decremented by 1/loop_step. So, if the loop_step was 13, the accumulator variable would be decremented by ‑1/13. After the loop ends, print the value of the accumulator variable.