Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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May I ask why the horizontal component of CD was neglected in the calculation of forces in the last part?
Transcribed Image Text:EXPLAIN
Additional examples are given in this section. For more explanations on trusses and frames
read Chapter 4 of your textbook.
1. Determine the force in each member of
the crane truss shown.
Solution:
6"
For the given crane truss, the member
forces can be determined without solving
for the support reactions.
B
9'
12'
30°
We can start our solution at joint A, since
there are only two unknowns at joint A.
5200 lb
Solve for the angle between member AC and AB:
Cosine law:
x = V(6)² + (9)² – (2)(6)(9) cos 120°
x = 13.08 ft
Sine law:
X.
sin a
sin 120°
1200
13.08
a = 23.41°
B
9'
Transcribed Image Text:ule4.pdf
AD IZUTU.74 IN
BD
+K Ey = 0
BC +12010.74 sin 30° = 0
%3D
%3D
BC = -6005.37 lb
BC = 6005.37 lb (C)
FBD of joint C:
+1 EV = 0
-CD sin 56.57° + 6005.37 cos 30° - 13088.08 sin 23.41° = 0
CE
%3D
56.57°
23.41°
CD = 0.96 lb 0
30°
AC=13088.08 lb
-6005.37 sin 30° + 13088.08 cos 23.41° – CE = 0
CE = 9008.05 lb (T)
%3D
BC=6005.37 ib
CD
117
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