Match the element to a set of quantum numbers allowed for the final electron placed in that element's electron configuration: (example: Oxygen has 8 electrons the electron configurtion is 1s22s22p4 the final electrons are placed in the 2p orbital so a possible set of quantum numbers are n=2, 1=1, m=0,ms=1/2) Sr Bi Pd - Bk (atomic number 97) A. n-5, 1-3, m₁=-2,mg=1/2 B. n=5, I=0, mi-1,mg=1/2 C. n=4, 1-2, m=1,mg=1/2 D. n=6, 1-2, m=-1,mg=1/2 E. n=5, I=0, mi=0,ms=1/2 F. n=4, 1-4, mi=-2,mg=1/2 G. n-6, I=1, m₁=-1,mg=1/2 H. n-6, 1-3, m₁=-2,mg=1/2

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Match the element to a set of quantum numbers allowed for the final electron placed in that element's electron configuration:
(example: Oxygen has 8 electrons the electron configurtion is 1s²2s²2p4 the final electrons are placed in the 2p orbital so a possible set of
quantum numbers are n=2, 1=1, m=0,ms=1/2)
Sr
Bi
✓Pd
✓ Bk (atomic number 97)
A. n=5, 1-3, m₁=-2,ms=1/2
B. n=5, I=0, m₁=1,ms=1/2
C. n=4, 1-2, m₁=1,ms=1/2
D. n=6, 1-2, m₁=-1,ms=1/2
E. n=5, 10, m₁=0,ms=1/2
F. n=4, 1-4, m₁=-2,ms=1/2
G. n-6, 1-1, m=-1,ms=1/2
H. n=6, 1-3, m₁=-2,ms=1/2
Transcribed Image Text:Match the element to a set of quantum numbers allowed for the final electron placed in that element's electron configuration: (example: Oxygen has 8 electrons the electron configurtion is 1s²2s²2p4 the final electrons are placed in the 2p orbital so a possible set of quantum numbers are n=2, 1=1, m=0,ms=1/2) Sr Bi ✓Pd ✓ Bk (atomic number 97) A. n=5, 1-3, m₁=-2,ms=1/2 B. n=5, I=0, m₁=1,ms=1/2 C. n=4, 1-2, m₁=1,ms=1/2 D. n=6, 1-2, m₁=-1,ms=1/2 E. n=5, 10, m₁=0,ms=1/2 F. n=4, 1-4, m₁=-2,ms=1/2 G. n-6, 1-1, m=-1,ms=1/2 H. n=6, 1-3, m₁=-2,ms=1/2
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