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make the Annotated Parse Tree based on the translation scheme below. S → B {A.i = B.val} A {S.val = A.s} A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s} A →  ɛ {A.s = A.i} B → D {C.i = D.val} C {B.val = C.s} C → * D {C1.i = C.i * D.val} C1 {C.s = C1.s} C → ɛ {C.s = C.i} D → ( S ) {D.val = S.val} D → num {D.val = num.val}

make the Annotated Parse Tree based on the translation scheme below. S → B {A.i = B.val} A {S.val = A.s} A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s} A →  ɛ {A.s = A.i} B → D {C.i = D.val} C {B.val = C.s} C → * D {C1.i = C.i * D.val} C1 {C.s = C1.s} C → ɛ {C.s = C.i} D → ( S ) {D.val = S.val} D → num {D.val = num.val}

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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2. Given the following statement: 6 * (8-3)
Please make the Annotated Parse Tree based on the translation scheme below.
S → B {A.i = B.val} A {S.val = A.s}
A → - B {A1.i = A.i - B.val} A1 {A.s = A1.s}
A →  ɛ {A.s = A.i}
B → D {C.i = D.val} C {B.val = C.s}
C → * D {C1.i = C.i * D.val} C1 {C.s = C1.s}
C → ɛ {C.s = C.i}
D → ( S ) {D.val = S.val}
D → num {D.val = num.val}

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