magnetic ring has a mean circumstance of 20 cm and a cross section of 20 cm2 and has 800 numbers of turns of wire. When the exciting current is 5 A, the flux is 2 mWb. The relative permeability of iron is nearly ?
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A magnetic ring has a mean circumstance of 20 cm and a cross section of 20 cm2 and has 800 numbers of turns of wire. When the exciting current is 5 A, the flux is 2 mWb. The relative permeability of iron is nearly ?
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- What will be the reluctance of a magnetic core if the mean path length for flux is 0.04 m and the cross-sectional area is 0.001 sq. m.? The relative permeability of the core is equal to (8000/n). Express your answer in ampere-turns per weber, rounded off to the nearest hundred [100 A- t/Wb]. Answer:A ferromagnetic core is shown in Figure Pl-2. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.005 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 800. 1-5. 10 cm- 5em 20 em 15 cm 15 cm 15 cm Coe depth - Scm SOLUTION There are three regions in this core. The top and bottom form one region, the left side forms a second region, and the right side forms a third region. If we assume that the mean path length of the flux is in the center of each leg of the core, and if we ignore spreading at the corners of the core, then the path lengths are I, = 2(27.5 cm) = 55 cm, I, = 30 cm, and /, = 30 cm. The reluctances of these regions are:For the magnetic circuit shown in the figure, the iron core with N = 500 turns -Magnetic permeability is 200. its average length is 10 cm -The diameter of the cross-sectional area is 1 cm. Find the current that must pass through the winding to produce 0.5 mWb of flux in a 1mm air-gap magnetic circuit?
- A ferromagnetic core is shown in Figure PI-2. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.005 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 1000. -10 cm- - 20 cm- 15 cm 400 turns 15 cm 15 cm Core depth 5 cmA ferromagnetic core is shown below. The depth of the core is 5 cm. The other dimensions of the core are as shown in the figure. Find the value of the current that will produce a flux of 0.003 Wb. With this current, what is the flux density at the top of the core? What is the flux density at the right side of the core? Assume that the relative permeability of the core is 1000. 1. - 10 cm--- - 20 cm - 15 cm 500 tums 15 cm 15 cm [1.21 A, 0.4 T, 1.2 T]The length of a magnetic circuit in a moving iron instrument is 300mm.The coil around the soft iron core has 360 turns and takes a current of 1.75A.The core is square in section with sides of 20mm.Take the relative permeability of soft iron as 1100. Determine the magnetomotive force in the core. Determine the field strength. Determine the flux density. Determine the total flux.
- The reluctance of a non-magnetic path is 12 AT-Wb. Find the flux needed to be set up if surrounded by a coil 600 turns carrying a current of 3 A.A toroidal core with a mean circumference of 100 cm and a cross-sectional area of 10 cm2 is wound with 500 turns of wire. What current would be required to generate a flux of 1 mWb in the core. Assume the core has a relative permeability of 800An iron core has a cross-sectional area of 10-3 square meter and mean circumference of 1 meter. The relative permeability of the material is 500 and the number of turns is 200. Determine the current required to set up a flux of0.001 weber. 7.54 A b. 7.96 A c. 8.19 A d. 8.47 A a.
- A magnetic circuit has a length of 100 cm and cross-sectional area of 5 square cm. The total flux is 10 x 10 webers. The coil has 100 turns and current of 4 amperes. What is the magnetic strength? a. 500 AT/m b. 400 AT/m c. 350 AT/m d. 450 AT/mAn iron circuit with a small0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (u, = 800 for iron). Figure 1An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm?, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (4, = 800 for iron). Figure 1