m2 frictionless pulley Στ=Ια T, T, I=-Mr 2 M a = alr M3 TA 370 M m, T m4

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Determine the linear acceleration of the system if m1 = 5kg, M = 0.750kg, m2 = 1kg, m3 = 1kg, m4 = 0.5kg, and m = 0.25, r1 = 0.3m, r2 = 0.2m, and the system is moving anti clockwise
T,
m2
T,
frictionless pulley
Στ= Ια
M
=-Mr?
2
a = alr
M3
T,
TA
m,
370
M
T
m4
Transcribed Image Text:T, m2 T, frictionless pulley Στ= Ια M =-Mr? 2 a = alr M3 T, TA m, 370 M T m4
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