A 215-g pendulum with a massless cord of length r = 1.00 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions theta = 90° and theta = 270°, its speed is 4.20 m/s. given (c) Find the magnitude of the tangential acceleration (in m/s2) for these positions. (d) Draw a vector diagram to determine the direction of the total acceleration for these two positions. (e) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration

A 215-g pendulum with a massless cord of length r = 1.00 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions theta = 90° and theta = 270°, its speed is 4.20 m/s. given (c) Find the magnitude of the tangential acceleration (in m/s2) for these positions. (d) Draw a vector diagram to determine the direction of the total acceleration for these two positions. (e) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration

Name: A 215-g pendulum with a massless cord of length r = 1.00 m swings in a
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: A 215-g pendulum with a massless cord of length r = 1.00 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions theta = 90° and theta = 270°, its speed is 4.20 m/s.given (c) Find the magnitude of the tangentia

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 30P: A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of...

See similar textbooks

Similar questions

A pendulum with a cord of length r = 1.00 m swings in a vertical plane (as shown). When the pendulum is in the two horizontal positions θ = 90.0° and θ = 270°, its speed is 5.00 m/s. Find the magnitude of (a) the radial acceleration and (b) the tangential acceleration for these positions.(c) Draw vector diagrams to determine the direction of the total acceleration for these two positions. (d) Calculate the magnitude and direction ofthe total acceleration at these two positions.
This figure (|a| = 20.0 m/s²) represents the total acceleration of a particle moving clockwise in a circle of radius r = 3.10 m at a certain instant of time. 30.0° (a) For that instant, find the radial acceleration of the particle. m/s² (toward the center) (b) For that instant, find the speed of the particle. m/s (c) For that instant, find its tangential acceleration. m/s² (in the direction of the motion)
A pendulum with a cord of length r = 1.20 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions = 90° and 9 = 270°, its speed is 5.10 m/s. (a) Find the magnitude of the radial acceleration (in m/s²) for these positions. m/s² (b) Find the magnitude of the tangential acceleration (in m/s²) for these positions. m/s² (c) Draw vector diagram to determine the direction of the total acceleration for these two positions. O i ar a magnitude direction 090° ā ar 0=270° a SAAU 0-90° 0 = 270° 090° ar 0 270° (d) Calculate the magnitude (in m/s²) and direction (in degrees above or below the horizontal) of the total acceleration. m/s² ---Select-- the horizontal at at 0= 90° 0=270 at ā
A pendulum with a cord of length r = 0.950 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions e = 90° and e = 270°, its speed is 4.60 m/s. (a) Find the magnitude of the radial acceleration (in m/s2) for these positions. m/s2 (b) Find the magnitude of the tangential acceleration (in m/s2) for these positions. m/s2 (c) Draw a vector diagram to determine the direction of the total acceleration for these two positions. ar à а, 0 = 90 0 = 270° 0 = 90 ° 0 = 270 at ar Ar а, a, 0 = 90° 0 = 270° 0 = 90° 0 = 270° (d) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration. magnitude m/s2 direction • -Select-- v the horizontal 10
This figure (|a| = 14.5 m/s²) represents the total acceleration of a particle moving clockwise in a circle of radius r = 3.20 m at a certain instant of time. 30.0° (a) For that instant, find the radial acceleration of the particle. m/s² (toward the center) (b) For that instant, find the speed of the particle. m/s (c) For that instant, find its tangential acceleration. m/s² (in the direction of the motion) Need Help? Read It Watch It
=J (e) (b) Fe= () 6. A pendulum that consists of a ball (m = 1.50 kg) attached to a light cord rotates in a circular path of radius r = 0.800 m at constant speed v, as shown in Figure. Here the angle 0 = 65°, and we ignore air friction and assume the mass of the light cord is negligible. (a) Calculate the tension T in the cord. = L. (b) Calculate the centripetal force acting on the ball. = 'd (c) Calculate the velocity v of this uniform circular motion. Answers:
A turntable has a diameter of 40.0 cm. It rotates at a rate of 40 revolutions per second (rps) thanks to the action of a motor. It slows its speed evenly to 15 rps in 10 seconds. Calculate: d) The magnitude of the total acceleration vector.e) The angle, in radians, for the turns in that time interval.f) The arc length traveled by a point on the saucer in that time interval.
A particle performs a uniform circular motion around the origin of the coordinate system. Consider the following statements: I) the acceleration vector points to the center of the trajectory. II) the velocity vector is constant. III) the dot product between the velocity and acceleration vectors is zero. Of these statements, only true are:
An automobile moves on a circular track of radius 1.02 km. It starts from rest from the point (x, y ) = (1.02 km, 0 km) and moves counterclockwise with a steady tangential acceleration such that it returns to the starting point with a speed of 29.3 m/s after one lap. (The origin of the Cartesian coordinate system is at the center of the circular track.) What are the car's position and velocity vectors when it is one-eighth of the way around the track? Express the vectors in terms of the unit vectors along the x- and y-axes.r = ( _____ i + _____ j) km v = ( _____ i + _____ j) m/s What is the tangential acceleration at this point?_______ m/s2What is the centripetal acceleration at this point?_______ m/s2
A Ferris wheel with radius 12.0 m is turning about a horizontal axis through its center in (Figure 1). The linear speed of a passenger on the rim is constant and equal to 6.40 m/s. A) What is the magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion? (Express your answer with the appropriate units.) B) What is the direction of the passenger's acceleration as she passes through the lowest point in her circular motion? (Is it "Towards the center" or "outwards from the center"?) C) What is the magnitude of the passenger's acceleration as she passes through the highest point in her circular motion? (Express your answer with the appropriate units) D) What is the direction of the passenger's acceleration as she passes through the highest point in her circular motion (Is it "Towards the center" or "outwards from the center"?) E) How much time does it take the Ferris wheel to make one revolution? (Express your answer with the appropriate units.…
ple 1. A particle moves along the curve F = (1³ − 41)î + (1² +41) ĵ + (81²-31³) k, where t is the time. Find the magnitude of the tangential components of its acceleration at t = 2.
A particle undergoes uniform circular motion on the xy plane with a radius of 19.6 m and an angular frequency of 3.1 rad/s. At time t = 0 the coordinates of the particle are x = 19.6 m and y = 0. The particle rotates in the counterclockwise direction. Determine the following at time t = 7.9 s: The components of the position of the particle y = m