m 10 B A positively charged particle is tied by a massless string and allowed to move on a smooth plane, as shown in the picture. A uniform magnet field B = 2 T is applied perpendicular to the plane pointing down. The length of the string is L = 50 cm. The mass of the particle is m = 55 k The charge on this particle is q = 0.6 C. The velocity of the motion is a constant v = 0.9265 m/s, in the clockwise direction when observing from above the plane. You can ignore friction. At a speed of v = 0.9265 m/s, how much is the Lorentz force (i.e. magnetic force) on the particle? (in units of Newton) Submit Answer Tries 0/2 To maitain the circular motion at this speed with a radius L, the net force Fnet on the particle is pointing to the center O. How much is Fnet? units of Newton) Submit Answer Tries 0/2 It is strongly recommended that you draw a free body diagram to answer the next two parts of the problem. How much is the tension in the string? (in units of Newton) Submit Answer Tries 0/2 If the particle moves in the opposite direction, but with the same speed v, how much is the tension in the string? (in units of Newton)

Let's take the Earth's magnetic field BE = 1.70 x 10-4 T pointing north. A metal cable attached to a space station stretches by 1.4 km. What would be the potential difference ( ΔΔ V) that develops between the ends of the cable if it’s traveling eastbound around Earth with a speed 4.4 km/s?

Two particles enter a region in space where there is a constant magnetic field B. Particle 1 has a mass of 2m, speed 3v, and unknown charge of q1. Particle 2 has a mass of m, speed v, and a charge with magnitude q2 = +2e. See figure. While in the field, the radius of motion for particle 1 is 3R and the radius of motion for particle 2 is R. See figure. Find B and q1. The knowns are m, v, R, and e. radius = 3R 3v ● B =? radius= R

See the attached figure for this problem. A charge of 9.26 x 10^6 C moves to the right as shown through a region containing both a magnetic field of strength 2.94 T directed into the screen and an electric field of strength 6.76 x 10^5 N/C directed downward. The charge continues through the region at a constant velocity (no acceleration). What is the charge s speed?

A proton is traveling through a region of space containing both a magnetic and electric field. At one instant in time, the velocity is U = (13500 Î + +38500) m/s and the acceleration is a = (4.39 k) x 10 m/s². If B=(9.21 k) mT, what is the magnitude of the electric field? i Save for Later N/C Submit Answer

A particle of mass m=3.1×10−5kg  and charge q=43μC  moves with a velocity v⃗ =−2.1×104ms−1 i^  along the x axis. a) Find the magnitude of magnetic field created by this charged particle at a distance d=37cm  from the x axis. Draw a schematic diagram. b) Now, if the charged particle moves in an uniform external magnetic field, B⃗ =−3.8T k^ , then calculate the magnetic force experienced by the charged particle in unit vector notation. x component of the magnetic force y component of the magnetic force z component of the magnetic force c) What will be the shape of the path of the charged particle moving in the uniform external magnetic field. Draw a schematic diagram and calculate a geometric quantity that can help you explain the path. d) Along with the external magnetic field, if we now apply an external electric field on the charged particle in a particular direction - the particle moves in a stright line. Explain why. And calculate the external electric field in unit vector notation.…

A proton, that is accelerated from rest through a potential of 55 kV enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, shown below. What is the proton's speed? Take mp 1.67 × 10-27 kg and e = = 1.6 × 10-¹⁹ C. P = E The magnetic field, B = (x) B (x) The speed, v = The E-field between the plates is 2.2 × 105 N/C. What B-field is required so that the protons are not deflected? Units Select an answer ✓ X Units Select an answer ✓

A charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 x 104 N/C and B = 0.4 T. %3D Hint a. What is the velocity of the charged particle? Velocity of the charged particle is x 104 m/s. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b) Mass-to-charge ratio of the part is kg/C. (Use the "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10´ 12".) - 12 enter "3.14E-