A proton, that is accelerated from rest through a potential of 55 kV enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, shown below. What is the proton's speed? Take mp = 1.67 × 10-27 kg and e = 1.6 × 10-19 C. P X 18||| B The magnetic field, B = The speed, v = The E-field between the plates is 2.2 × 105 N/C. What B-field is required so that the protons are not deflected? Units Select an answer Units Select an answer

Consider two protons trapped on the same geomagnetic field line.  One proton has kinetic energy 10 eV and the other has kinetic energy of 10 keV.  Which statement about the magnetic field strength at their respective mirror points is correct? A. B10 eV < B10 keV B. B10 eV > B10 keV C. B10 eV = B10 keV D. Not enough information is given

A particle with mass 1,67x10-3 kg and charge of +1.32x10-8 C has, at a given instant, a velocity of 2.90x10 m/s along the +-axis, as shown in the figure. (Figure 1) Figure 1 of 1 45.0° C X Part A What is the magnitude of the particle's acceleration produced by a magnetic field of magnitude 1.19 T in the -y plane, directed at an angle of 45.0" counterclockwise from the +-axis? Express your answer with the appropriate units to three significant figures. 0.178 m Submit Previous Answers Request Answer Part B ? * Incorrect; Try Again; 3 attempts remaining +-direction -a-direction What is the direction of the particle's acceleration?

What is the maximum force on a rod with a 0.100 µC charge that you pass between the poles of a 1.79 T strength permanent magnet at a speed of 3.12 m/s? N

A particle with charge q and and speed venters a region of magnetic field B1 and is deflected from its path into a region with field B2. It enters the second region moving vertically and exits horizontally.   a) Draw a sketch of the path of the particle. b)The particle exits the second region at a height d, measured from the interface of the two regions. What is the mass of the particle?

A particle with charge 0.350 C is initially traveling at 90.0 m/s along the +y-direction and encounters a magnetic field of 1.30x10-2 T along the +x-direction. Part A What is the magnitude of the force on the charge? n ΑΣφ ? F = N Submit Request Answer Part B What is the direction of the force? O +x direction -x direction +y direction O -y direction +z direction O -z direction O O O O O C

At a particular instant, a proton, far from all other objects, is located at the origin. The proton is traveling with velocity (-8 × 106, 0, 0)m/s. Consider the electric and magnetic fields at observation point (8 × 10-¹⁰,5 × 10-¹0,0)m caused by this proton. What is the electric field at the observation point? 1.37E9 1.37×10⁹ 9 1.37E9 X 1.37×10⁹ 9 0 0

A cyclotron (figure) designed to accelerate protons has an outer radius of 0.333 m. The protons are emitted nearly at rest from a source at the center and are accelerated through 572 V each time they cross the gap between the dees. The dees are between the poles of an electromagnet where the field is 0.720 T. The black, dashed, curved lines Alternating AV represent the path of the particles. -Dg After being accelerated, the particles exit here. -North pole of magnet (a) Find the cyclotron frequency for the protons in this cyclotron. 1.04e33 x rad/s (b) Find the speed at which protons exit the cyclotron. m/s (c) Find their maximum kinetic energy. ev (d) How many revolutions does a proton make in the cyclotron? revolutions (e) For what time interval does the proton accelerate? awranca Barke kay Nationallab

A 68.0-cm-diameter cyclotron uses a 450 V oscillating potential difference between the dees. Part A What is the maximum kinetic energy of a proton if the magnetic field strength is 0.740 T? Express your answer with the appropriate units. Value Submit Part B μA Submit Units Request Answer IV—| ΑΣΦ 3 How many revolutions does the proton make before leaving the cyclotron? ? Request Answer ?

An electron encounters an E and B fields.B field is given by B = 0.1 j T.Electron experiences a force F = (9.6 x 10^-14 i – 9.6 x 10^-14 k)Find the electric field encountered by the electron. The velocity of the electron isv = 5 x 10^6 i m/s.