Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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A female from true breeding line of Drosophila with white eyes is crossed with a male from a true breeding line with brown eyes. All of the offspring have wild type brick red eyes. Which of the following explanations is most likely?
A) There are many alleles for the single gene for eye color. Wild type brick red eyes result only when the fly is heterozygous.
B) The alleles for brown, white, and brick red eyes are alleles for a single locus. The allele for brown eye color is dominant to the allele for brick red eye color and to the allele for white eyes.
C) There is more than one gene for eye color. The brown mutation and the white mutation occur in separate genes and are both recessive to the wild type alleles. The offspring are heterozygous for both genes, so they are phenotypically wild type.
D) None of the above. It is not possible for a cross between a white-eyed and a brown-eyed fly to produce wild type offspring.
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- In an attempt to breed winter barley that is resistant to barley mosaic virus, agricultural researchers cross a susceptible domesticated strain with a resistant wild strain. The F1 plants are all susceptible, but when the F1 plants are crossed with each other, some of the F2 individuals are resistant. Is the resistance allele recessive or dominant? (Note: susceptible means able to get the viral disease, while resistant means not able to get the disease) A) The resistance allele must be recessive B) The resistance allele must be dominantarrow_forwardA homozygous fly with two recessive mutations causing purple body and short wings (ppss) is mated with a fly heterozygous for both mutations (p+p and s+s): "+" represents the wild-type allele. They have the following offspring: 26 Wild type (normal body, normal wings) 345 Purple body, normal wings 376 Normal body, short wings 13 Purple body, short wings What is the allele arrangement (haplotype) for the heterozygous parental fly? ("p" designates the mutant allele; "p+" designates the wild-type allele.)arrow_forward):):));;$;$:&:&:arrow_forward
- a) 1/3 b)1/2 c)1/8arrow_forwardIn Drosophila, the allele for long legs (sl*) is wild-type and the allele for short legs (sl) is mutant. The allele for gray body color (b*) is wild-type and the allele for black body color (b') is mutant. The loci for leg length and body color are linked. Flies with sl*sl* b*b* genotypes are mated with flies that have sl s bb genotypes. A testcross was then performed in which the F, offspring with sl*sl b*b genotypes were mated with flies with sl sl. b'b genotypes. The phenotypes of 1000 offspring were recorded. There were 470 flies with long legs and grey body, 30 flies with long legs and black body, 30 flies with short legs and grey body, and 470 flies with short legs and black body. Which of these phenotypes are parental phenotypes? VWhich of these phenotypes are recombinant phenotypes? What is the distance between these two gene loci in centiMorgans (map units)?arrow_forwardThe answer is "D" but can you explain in a short summary why D is the answer pleasearrow_forward
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