Liquid kerosene flows through a Venturi meter. The pressure of the kerosene in the pipe supports columns of kerosene that differ in height by 12 cm. Determine the difference in pressure between points a and b, in kPa. Does the pressure increase or decrease as the kerosene flows from point a to point b as the pipe diameter decreases? The atmospheric pressure is 101 kPa, the specific volume of kerosene is 0.00122 m³/kg, and the acceleration of gravity is g = 9.81 m/s². Kerosene Pa 101 kPa 8-9.81 m/s² = 0,00122 kg/m³ L=12 cm

Introduction

In this problem, we will compute the pressure difference between points a and b by first calculating the pressure at limb a and pressure at limb b, and then calculating the pressure difference between points a and b while taking into account the atmospheric pressure effect.

Given data:

$\begin{array}{rcl}\mathrm{the} \mathrm{difference} \mathrm{of} \mathrm{height} \left(\mathrm{h}\right)& =& 12 \mathrm{cm}\\ \mathrm{the} \mathrm{pressure} \mathrm{at} \mathrm{column} \mathrm{A} \left(\mathrm{P}\right)& =& 101 \mathrm{kPa}\\ \mathrm{the} \mathrm{specific} \mathrm{volume} \mathrm{of} \mathrm{kerosene} \left(\mathrm{v}\right)& =& 0.00122 {\mathrm{m}}^3/\mathrm{kg}\\ \mathrm{the} \mathrm{acceleration} \mathrm{due} \mathrm{to} \mathrm{gravity} \left(\mathrm{g}\right)& =& 9.81 \mathrm{m}/{\mathrm{s}}^2\end{array}$

Determine:

The difference in the pressure between point a and point b.