LINK LAYER (AND NETWORK LAYER) ADDRESSING AND FORWARDINGConsider the figure below. The IP and MAC addresses are shown for nodes A, B, C and D, as well as for the router's interfaces.1F-2C-5D-67-62-8E128.119.134.90QUESTION 1 OF 5What is the source mac address at point 5?Answer6A-A4-2E-AB-94-D3128.119.81.211Consider an IP datagram being sent from node D to node C.(2)BFA-7C-90-45-8C-1D128.119,134,239(3)72-F0-35-56-CA-42128.119.81.191(4)47-FF-04-D4-B3-27128.119.20.251CC-CF-5A-C7-02-03128.119.20.75(6)(5)D5E-C8-B0-3D-5D-DE128.119.20.91

The source MAC (Media Access Control) address is a unique hardware address assigned to the network…

LINK LAYER (AND NETWORK LAYER) ADDRESSING AND FORWARDING Consider the figure below. The IP and MAC addresses are shown for nodes A, B, C and D, as well as for the router's interfaces. 1F-20-5D-67-62-8E 128.119.134.90 (1) QUESTION 1 OF 5 Answer What is the source mac address at point 5? 6A-A4-2E-AB-94-D3 128,119,81.211 Consider an IP datagram being sent from node D to node C. (2) FA-7C-90-45-8C-1D 128.119.134.239 (3) 72-F0-35-56-CA-42 128,119.81.191 47-FF-04-D4-B3-27 128,119,20,251 CC-CF-5A-C7-02-03 128.119.20.75 5E-C8-B0-3D-5D-DE 128.119.20.91

LINK LAYER (AND NETWORK LAYER) ADDRESSING AND FORWARDING Consider the figure below. The IP and MAC addresses are shown for nodes A, B, C and D, as well as for the router's interfaces. 1F-20-5D-67-62-8E 128.119.134.90 (1) QUESTION 1 OF 5 Answer What is the source mac address at point 5? 6A-A4-2E-AB-94-D3 128,119,81.211 Consider an IP datagram being sent from node D to node C. (2) FA-7C-90-45-8C-1D 128.119.134.239 (3) 72-F0-35-56-CA-42 128,119.81.191 47-FF-04-D4-B3-27 128,119,20,251 CC-CF-5A-C7-02-03 128.119.20.75 5E-C8-B0-3D-5D-DE 128.119.20.91

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter13: Internet And Distributed Application Services

Section: Chapter Questions

Problem 15VE

See similar textbooks

Similar questions

Refer to the network figure above, showing two Ethernet Subnets connected through an IP Router, answer the following question 1-5. The devices in each subnet are connected locally to each other through layer two intermediate devices such as Ethernet switch and ethernet hub. For each device in the subnets, both its Internet Protocol (IP )address and its MAC address (also called the Physical address or the Ethernet address are shown. The subnet mask used by all devices is 255.255.255.240 (which is the same as the prefix length “/28”). 1. If Client #1 wants to send a broadcast packet to all the devices on the left subnet (containing client #1, client #2, client #3) what destination IP address should be used? (Mention in both binary and decimal format.) 2. What is the first and last assignable IP address for the left subnet above (containing client #1 and #3)? (Mention in both binary and decimal format.)
Consider the figure below. The IP and MAC addresses are shown for nodes A, B, C and D, as well as for the router's interfaces. Consider an IP datagram being sent from node D to node A. Give the source and destination Ethernet addresses, as well as the source and destination addresses of the IP datagram encapsulated within the Ethernet frame at points (5), (4), (2), and (1) in the figure above.
An IP address can be written as a 32-bit number. For a class B network, the two most significant bits are set to 10. The 16 most signi cant bits are used as a network ID, and the 16 least signi cant bits are used as a host ID. However, the host ID cannot be all 0's or all 1's. How many hosts (i.e., host IDs) can there be on a class B network?
2. Subnetting a subnet or using variable-length subnet mask (VLSM) was designed to maximize addressing efficiency. You are required to subnet, based on the number of hosts, including router interface and WAN interface and WAN connections for the following scenario: •Toronto: 60 host addresses •Montreal: 28 host addresses •Ottawa: 12 host addresses •Vancouver: 12 host addresses •WAN1: 2 host addresses •WAN2: 2 host addresses •WAN3: 2 host addresses Using the given address block of 192.168.15.0/24, you can design an address scheme for the network to meet its requirements and save potential addresses. The data for Toronto is given to help you to fill the remaining all other columns. Name Toronto Montreal Ottawa Vancouver WAN1 WAN2 WAN3 Required no of addresses 60 28 12 12 ~~ 2 2 2 Subnet Address 192.168.15.0 Address Range .1 - .62 Broadcast Address .63 Network/ Prefix 192.168.15.0 /26 19
The table below belongs to the bridge in Figure 4 MAC Address Interface No Date/Time 65-FD-B7-81-39-C5 1 10:15 9C-FA-B2-B8-71-50 3 10:16 Within collision domain of Department of Electric and Electronics Engineering in Figure 4, there exists a host (Host#1) with 9C-FA-B9-BB-71-50 MAC address. There is another host (Host#2) with 65-FE-B8-99-39-D5 MAC address within the collision domain of Food Engineering in Figure 4. Host #1 sends a frame to Host #2. How will the bridge handle this transmission? What will it do? Explain the transmission step-by-step in reason until the frame is transmitted to the destination host.
NAT translation table LAN side addr WAN side addr 135.122.200.215 10.0.1.15 10,0.1.13 address 135.122.200.215 S: 10,0,1.27 2 D: 1 D: S: S: D: S: 10,0.1.15 D: 135.122,200,215 10.०.1.22
SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 : A 175 hosts QUESTION 2 OF 10 Answer How many hosts can there be in this address space? 144.145.110.0/23 B Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. 84 hosts
An IP address can be written as a 32-bit number. For a class B network, the two most significant bits are set to 10. The 16 most significant bits are used as a network ID, and the 16 least significant bits are used as a host ID. However, the host ID cannot be all 0's or all 1's. How many hosts (i.e., host IDs) can there be on a class B network?
SUBNET ADDRESSING Consider the router and the two attached subnets below (A and B). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 144.145.110.0/23 175 hosts QUESTION 3 OF 10 A Answer What is the subnet address of subnet A? (CIDR notation) 144,145.110.0/23 Assign subnet addresses to each of the subnets (A and B) so that the amount of address space assigned is minimal, and at the same time leaving the largest possible contiguous address space available for assignment if a new subnet were to be added. Then answer the questions below. B 84 hosts
A data link layer switch SW1 is connected with four hosts (H1, H2, H3, H4) as shown in figure below: Suppose switch table is empty and switch receives a frame with source MAC address of H1 (MAC-H1) and destination MAC address of H2 (MAC-H2). What actions will be performed by the switch in this case?
19. ARP is used for: O packet path determination O finding of a mapping IPV6 → MAC address O finding of a mapping IPV4 → MAC address O finding of a mapping IPV4 → TCP address
Consider a datagram network using 32-bit host addresses. Suppose a router has four links, numbered 0 through 3, and packets are to be forwarded to the link interfaces as follows: Destination Address Range Link Interface 11100000 00000000 00000000 00000000 through 11100000 00111111 1111111 11111111 11100000 01000000 00000000 00000000 through 11100000 01000000 1111111111111111 11100000 01000001 00000000 00000000 through 11100001 01111111 11111111 11111111 otherwise 0 1 2 3 a. Provide a forwarding table that has five entries, uses longest prefix matching, and forwards packets to the correct link interfaces.