LEVEL OF ANXIETY Low Medium 10 Toddler Pre-school AGE Grade school 10 10 10 15 High school College 15 20 20 30 The outcome matrix shown above represents a design. O5x2 5x 10 single factor x multi-factor age x grade none of the above
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- Cranberry juice It’s common folk wisdom that drinkingcranberry juice can help prevent urinary tract infections inwomen. In 2001 the British Medical Journal reported theresults of a Finnish study in which three groups of50 women were monitored for these infections over 6months. One group drank cranberry juice daily, another group drank a lactobacillus drink, and the third drank nei-ther of those beverages, serving as a control group. In the control group, 18 women developed at least one infection,compared to 20 of those who consumed the lactobacillusdrink and only 8 of those who drank cranberry juice. Doesthis study provide supporting evidence for the value ofcranberry juice in warding off urinary tract infections?a) Is this a survey, a retrospective study, a prospectivestudy, or an experiment? Explain.b) Will you test goodness-of-fit, homogeneity, orindependence?c) State the hypotheses.d) Test the conditions.e) How many degrees of freedom are there?f) Find x2and the P-value.g) State…A two-factor study investigates the effects of self-esteem (low vs. high) and gender (males vs. females) on anxiety scores. The following data represents the means for each treatment condition. Low self-esteem High self-esteem Male 5 11 Female 10 3 The data shows that there is a self-esteem by gender interaction. Explain the self-esteem by gender interaction (include individual means in your explanation)Suppose that experiment to see if taking vitamin C, vitamin D, or both, help prevent or reduce cold symptoms was conducted based on a random sample of 1981 individuals, Subjects were assigned to receive vitamin C only, vitamin D only, vitamin C and D, or placebo, and then were monitored for the duration of the cold season to see if they developed a cold or not. The results were tabulated in a two-way table in which the column variables were the vitamin supplements and the row variables were the cold responses. Researchers then conducted a chi-square test for independence to see if cold responses and vitamin supplements are dependent. How many degrees of freedom does the chi-square statistic have? df=
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