Let Z be a standard normal random variable. Use the z‐table to find P(Z > ‐1.30)?

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A: Given, Z~N(0,1) P(-c<Z<c)=0.9749

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A: Given information, μ=19n=13x¯=18.1s=3.3 df=n-1=13-1=12

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Q: Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine…

A: From the provided information, P (-c ≤ Z ≤ c) = 0.9371

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Q: If Zis a standard normal random variable, then P(-1.25 ≤ Z ≤ -0.75) is: Select one: O O a. 0.1210 b.…

A: Z is a standard normal random variableP(-1.25z-0.75)

Q: ind P(Z < 2.04) where Z is the standard normal random variable. Round to 4 decimal places. Answer:

A: given data  standard normal distribution Z~N(0,1) P(z&lt;2.04) = ?

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Q: Given that z is a standard normal random variable, compute P(z < 1.1). Select one: O a. 0.9192 O b.…

A: The value can find from standard normal table

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A: Required probability is P(Z&gt;1)

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A: Standard normal distributionZ~N(0,1)

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Q: Find the following probability for the standard normal random variable z. e. P(z 20) f. P(-2.54…

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Q: Let Z be a standard normal random variable. Use the calculator provided to determine the value of c.…

A: We have find z- score...

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Q: Find P(Z > 1.6) where Z is the standard normal random variable. Round to 4 decimal places. Answer:

A: given data  standard normal distribution  Z~N(0,1) P(Z≥1.6) = ?

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A: Option (c) is correct

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A: Given Mean=3.33 Standard deviations=0.71 n=6

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Q: Let Z be a standard normal random variable. Calculate P(-1.064 < Z).

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A: Here, mean is 3.86 and standard deviation is 0.99. Sample is 7. We will use sampling distribution.

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A: P(z ≥ 2.48)

Q: Let Z be a standard normal random variable. Determine the value of c. P ( Z ≤ c) = 0.1515

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