Customers can replace 1, 2, 3, or 4 tires at a time for their vehicle at Thrifty Tires, a nationwide tire shop chain. For customers who have had their tiresreplaced at Thrifty Tires, the mean number of tires replaced is u = 3.33, with a standard deviation of o = 0.71. Suppose that we will take a random sample ofn=6 tire replacement orders. (Each order gives the number of tires being replaced.) Let x represent the sample mean of the 6 tire replacement orders.Consider the sampling distribution of the sample mean x.Complete the following. Do not round any intermediate computations. Write your answers with two decimal places, rounding if needed.(a)Find u- (the mean of the sampling distribution of the sample mean).H = |?(b) Find o- (the standard deviation of the sampling distribution of the sample mean).O

Given Mean=3.33 Standard deviations=0.71 n=6

Answered: Customers can replace 1, 2, 3, or 4…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If we meet these conditions, the sampling distribution of the mean will have a normal shape and ... The mean of the sampling distribution will be u, (i.e., the same as the population mean) and the standard deviation of the sampling distribution will be (that's the population standard deviation divided by the square root of the sample size). In the AP Stats Guy video, he talks about the number of text messages his students send during class. Suppose the average number of text messages his students send during class is u = 30 text messages. If we take samples of say, n = 36 students at a time, we would expect the mean of the sampling distribution we create to be the same as the population mean, 30 text messages. If we can further say that standard deviation of the number of text messages is 12 text messages, by how much would we expect the sample means to vary? (hint, use the formula above) text messages

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