Let x be a ramdom variable that represents the height in inches, of an adult 18 years or older female in the US then x has an approximately normal distribution with a mean=63.5 and standard deviation = 3 find the probability that a ramdomly chosen adult female in the US is at most 66 inches tall. Hint: you must find P(x is at least 66 in)

On average indoor cats live to 14yrs oldvwith a standard deviation of 2.4 yrs.Suppose the distribution is normal.Let X = the age at death of a randomly selected indoor cat.Round answers 4 decimal places where possible. The middle 30 % of indoor cats age of death lies between what two numbers? Low=   yrs High=    yrs

A normal distribution has mean u= 56 and standard deviation o = 20. Find and interpret the z-score forx=59. The z-score for x = 59 is So 59 is standard deviations (Choose one) v the mean u = 56.

The average American man consumes 9.7 grams of sodium each day. Suppose that the sodium consumption of American men is normally distributed with a standard deviation of 1 grams. Suppose an American man is randomly chosen. Let X = the amount of sodium consumed. Round all numeric answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N Note: this shows 2 blank spots for answers

Assume that blood pressure readings are normally distributed with a mean of 124 and a standard deviation of 4.8. If 36 people are randomly selected, find the probability that their mean blood pressure will be less than 126. OA. 0.8615 OB. 0.8819 OC. 0.0062 O D. 0.9938 C...

The average amount of money spent for lunch per person in the college cafeteria is $6.24 and the standard deviation is $2.05. Suppose that 6 randomly selected lunch patrons are observed. Assume the distribution of money spent is normal, and round all answers to 4 decimal places where possible.What is the distribution of ¯x?

Systolic blood pressure readings are normally distributed with a mean of 121 and standard deviation of 15. If a person from the population was selected at random, find the probability that their blood pressure is in the acceptable range (between 114 and 140) for an athletic activity.  A. Label and shade the normal distribution curve to model this problem.

n=16  mean number of  television per household is 4 with a standard deviation of 1 television. using chebychev's theorem, detemine at least how many households have between 2 and 6 television.

Assume that adults have IQ scores that are normally distributed with a mean of u = 105 and a standard deviation o = 15. Find the probability that a randomly selected adult has an IQ between 89 and 121. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 2) The probability that a randomly selected adult has an IQ between 89 and 121 is (Type an integer or decimal rounded to four decimal places as needed.) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 5279 .5319 .5359 0.1 .5398 .5438 5478 .5517 .5557 .5596 ,5636 ,5675 .5714 .5753 0.2 .5793 .5832 5871 5910 .5948 .5987 .6026 .6064 .6103 .6141 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.5 .6915 6950 .6985 7019 .7054 .7088 7123 7157 .7190 .7224 0.6 .7257 .7291 7324 7357 7389 7422 7454 7486…