Let (:/ be an inner product in the vector space V. Given an isomorphism1' : U + [u, v] = (Tu, Tv), for any u, V E U. Check thatl lis an in-house product. Note: From the internal product (:) define a new "internal product (with the mentioned cone the inner product axioms must be verified in this new function u, v] = (Tu, Tv)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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linear algebra 

Let (: ) be an inner product in the vector space V. Given an isomorphismT : U + V. Score
[u, v] = (Tu, Tv), for any u, V E U. Check that Jis an in-house product.
Note:
From the internal product (:) define a new "internal product (with the mentioned conditions)
the inner product axioms must be verified in this new function (u, v] = (Tu,Tv)
i [uiv]=[viu]
i.
i [urr,w] =
آس، کا
[uiw] +[uiw]
%3D
w. [uiu] 70
Yu
[uiu] =0 u=0
using the fact that T is an isomorphism
Transcribed Image Text:Let (: ) be an inner product in the vector space V. Given an isomorphismT : U + V. Score [u, v] = (Tu, Tv), for any u, V E U. Check that Jis an in-house product. Note: From the internal product (:) define a new "internal product (with the mentioned conditions) the inner product axioms must be verified in this new function (u, v] = (Tu,Tv) i [uiv]=[viu] i. i [urr,w] = آس، کا [uiw] +[uiw] %3D w. [uiu] 70 Yu [uiu] =0 u=0 using the fact that T is an isomorphism
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Let , be an inner product in the vector space V and  given an isomorphism T : UV.                     u, v=Tu, Tv, for any u, vU

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