<- Part A The value of AH" for the reaction below is -186 kJ. H2 (g) + Cl2 (g) → 2HCI (g) The value of AH, for HCI (g) is kJ/mol. -1.27 x 102 -186 0-93.0 +186 O-3.72 x 102 Submit Request Answer Provide Feedback SC < 1 @ 2 Q W σ #3 $ 4 A4 % a15 MacBook Pro 66 E R T Y & 7

DATA AND CALCULATIONS Reaction 2 Reaction 3 Reaction 1 (no solid NaoH) 2154 100. 154 a8.5 Mass of NaOH solid 100 t00.061 34.8 d1.9 Mass (total) of solution 6. 9. 6. °C 33.3 °C Final temperature, T2 °C av. °C al. 7 Initial temperature, T °C °C CALCULATIONS temperature change, AT 6.7 °C la. 9 °C I1.6 °C kJ -5395.489 k-4848.8 -ag04.913 a804.913 k- $395.499 KJ|-4848.8 Heat, q kJ ΔΗ k) Moles of NaOH 0.054 mol 0.0515 0.05 mol mol AH/mol -51,942.83k)/mol-104 96.70kJ/mol-96 976 kJ/mol Experimental value kJ/mol Accepted value k)/mol Percent error %

please help! use correct sig figs and/or scientific notation! Multiple part question and very confused. Also, at the end what would be the equilibrium constant for this reaction at 2500 ºC.

Traduction: Given the reaction: determine the entalpy change for the next ecuation: 8. Dada la reaccion 4AICI3(s) + 302(g) → 2Al2O3(s) + 6CI2(g); AH= -529.0 kJ %3D determine AH para la siguiente rea ión Cl2(g) + %Al2O3(s) %AICI3(s) + ½O2(g) +529.0 kJ +88.2 kJ +176.3 kJ +264.5 kJ a)

For the reaction N2(g) + O2(g)→2NO(g) AH° = 181 kJ and AS° = 24.9 J/K AG° would be negative at temperatures (above, below) K. Enter above or below in the first box and enter the temperature in the second box. Assume that A H° and AS° are constant.

Σ * 00 For a particular reaction at 221.2 °C, AG = -700.77 kJ, and AS = 684.38 J/K. %3D Calculate AG for this reaction at -30.3 °C. %3D = DV 8:13 PM 11/8/2021 F12 PrtScr Insert Delete F8 F10 F11 Backspace 24 B. Alt Ctrl Home it

How to solve this question pls