Learning Goal: As shown, a differential element of material is distorted after it is subjected to stresses resulting in a state of plane strain given by = -360.0 x 10-6 in/in. Ey= 225.0 x 10-6 in/in, and Yzy = 110.0 x 10-6 in/in (Figure 1) Figure & dy I 1 dy 2 & dx de B < 1 of 1 > Yay ▼ ▼ Part B - Maximum in-plane shear strain and its orientation Determine the magnitude of the maximum in-plane shear strain, Yin plane and its orientation relative to the differential element of material. Express your answers to four significant figures separated by a comma. ► View Available Hint(s) max in plane = Submit ΠΕ ΑΣΦ 4 vec S → 12 A Part C - Average normal strain in the differential element of material Determine the average normal strain in the differential element of material. Express your answer to four significant figures. ► View Available Hint(s) ? in/in, rad

Learning Goal: As shown, a differential element of material is distorted after it is subjected to stresses resulting in a state of plane strain given by = -360.0 x 10-6 in/in. Ey= 225.0 x 10-6 in/in, and Yzy = 110.0 x 10-6 in/in (Figure 1) Figure & dy I 1 dy 2 & dx de B < 1 of 1 > Yay ▼ ▼ Part B - Maximum in-plane shear strain and its orientation Determine the magnitude of the maximum in-plane shear strain, Yin plane and its orientation relative to the differential element of material. Express your answers to four significant figures separated by a comma. ► View Available Hint(s) max in plane = Submit ΠΕ ΑΣΦ 4 vec S → 12 A Part C - Average normal strain in the differential element of material Determine the average normal strain in the differential element of material. Express your answer to four significant figures. ► View Available Hint(s) ? in/in, rad

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter3: Transient Heat Conduction

Section: Chapter Questions

Problem 3.4P

See similar textbooks

Similar questions

Topic: Calculation of stretch: small es. finite deformation Consider the mapping in 2-D only 21 = X1 +7X2 = X1+ u1 82 = (1+e)X2 = X2 + Uz. (1) 1. In terms of y and a compute F, i.e. the Fij's and then compute the Cj = FF.j; recall F = Fi. Now do the following. %3D 2. Take two fibers, viz. dX = e and dY = e2, that is two fibers of unit length along the ej and ez axes, respectively in the reference state. Compute the stretch of dX and dY. 3. Compute the small strains from this mapping with u = 7X2 and ur = eX¡ from above. What would these small strains suggest for the change in lengths of dX and dY? 4. Comment on what you found from the results of 2. and 3. You may want to sketch the deformed state to explain your comments.
Use the chart given in the textbook Shigley's Mechanical Engineering Design, 10th Ed. Figure 2-16). **I need a step by step solution Please**
Answered: T Blackboard @ Texas X Bb MasteringEngineering - Spring 2 × E MasteringEngineering Mastering x > (195) Find the resultant force acti X O (195) Morgan Wallen - Cover i session.masteringengineering.com/myct/itemView?assignmentProblemID=12360390 ABP G I Review Suppose that h = 4 m. (Figure 1) Part C Determine the coordinate direction angle B of the resultant force of the two forces acting on the sign at point A. Express your answer using three significant figures. B = 90 Submit Previous Answers v Correct Part D Figure 1 of 1 Determine the coordinate direction angle y of the resultant force of the two forces acting on the sign at point A. 2 m Express your answer using three significant figures. E 2 m B Hν ΑΣφ ? vec F = 350 N Fc= 400 NA F = 400 N 2 m Submit Request Answer 3 m Provide Feedback Next > 11:50 PM O Type here to search 2/7/2021
2. Below is a picture of a car suspension system with additional springs (in red) added in series. Assume the car remains "level" (i.e. no rotational motion of the car body, only vertical motion). The original springs are ks modeling tire/road interaction). The car mass is m = 2,000 kg. 20, 000 N/m (the suspension spring), and kt 100, 000 N/m (the spring %3D The springs are all in equilibrium when d = 0.4 m. Ignore gravity in this problem. The point of the additional spring k is to make the ride more "bouncy" (some people like it that way). However, you need to make sure the car does not "bottom out" (i.e. hit the bump). It is known that when the springs are unstretched/uncompressed, the marimum vertical velocity can be is 1 m/s. What is the minimum value of the spring constant k (of the additional red spring) so that the car does not hit the bump during its vertical oscillations. Hint: Use energy balance. kis k's kt Figure 4: Simplified car model with upper springs representing…
Q: Figure 2 shows a typical mast from a modern racing yacht. It is built in the form of a thin-walled tube (hallow cylinder). To win long-haul ocean races, these yachts need to have every advantage that high-performance materials can give, in terms of maximum stiffness (must not easily deflect), plus minimum weight as possible. The following are the equations to use: 1(F13 8 == 8 EI and I = ar³t, A = 2art assume l and cross section are fixed but thickness t is free to change. • Drive the performance index for this problem • Use table 1 to select top three materials with the best performance index. Figure 2 Table. 1 Data for Tube of Given Stiffness p (Mg.m 3) 2.0 Material E (GPa) GFRP 12 Steel 7.8 200 Wood 0.6 12 Aluminum alloy Titanium alloy 2.7 69 4.5 120
Hello. Answer is s=0.42m (how far the spring goes down before stopping the object falling). I am uploading this question as the example answer's working out was bad I find it hard to follow. I would like to see working out how the calculations equate to the answer being s=0.42m
I Review Learning Goal: Part A- Vertical impact To calculate displacement and stresses due to vertical and horizontal impact loads. A 10-kg block is dropped from 1.5 m onto the center of a simply supported beam with a length 3 m. The beam has a square section with side length 6.5 cm. The material has E = 200 GPa . What is the maximum deflection? When an object strikes a structure that responds by deforming in linear elastic fashion, the object comes to rest when the structure has undergone maximum deflection. At that moment, the structure's strain energy must equal the sum of the energies before the impact, including both the object's kinetic energy and its gravitational potential energy. Express your answer with appropriate units to three significant figures. > View Available Hint(s) When an object falls from rest onto a structure, the object's gravitational potential energy is converted into strain energy in the structure. The total strain energy in the structure at the point of…
From the matrix can you show me how the value stiffness (k) calculated?
Learning Goal: As shown, a massless string is wrapped around a pulley of radius r and mass m. (Figure 1) The string's other end is attached to a block with mass m. The pulley can rotate freely about its axis and its cylinder is uniform. Note that the positive y direction is downward and that counterclockwise moments are positive. Figure 99°F Sunny 1 of 1 Provid
E and 5 v X O file:///C:/Users/Hp/Desktop/mm/OUTCOME%20NO.2%20and%205%20with%20Problems.pdf + O Fit to page D Page view A Read aloud 1 Add notes Problems 1. A brass rod of diameter 25 mm and length 250 mm is subjected to a tensile load of 50 kN and the extension of the rod is equal to 0.3 mm. Find the Young's Modulus or Modulus of Elasticity. 99+ to search hp delete prt sc 14 DI backs & 7 8 24 4 P EJR -0 J K H D. F
Learning Goal: To calculate the normal and shear stresses at a point on the cross section of a column. A column with a wide-flange section has a flange width b = 250 mm , height k = 250 mm , web thickness to = 9 mm , and flange thickness t; = 14 mm (Figure 1). Calculate the stresses at a point 65 mm above the neutral axis if the section supports a tensile normal force N = 2 kN at the centroid, shear force V = 5.8 kN , and bending moment M = 3 kN - m as shown (Figure 2). The state of stress at a point is a description of the normal and shear stresses at that point. The normal stresses are generally due to both internal normal force and internal bending moment. The net result can be obtained using the principle of superposition as long as the deflections remain small and the response is elastic. Part A- Normal stress Calculate the normal stress at the point due to the internal normal force on the section. Express your answer with appropriate units to three significant figures. • View…
Calculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du, DN4Du, DN5Du, DN6Du,DN7Du,…