From the matrix can you show me how the value stiffness (k) calculated? 6 for [kma -Ka+ K2X =0mim, oKi+k2- KaMa- K2Kamamin By Eigenvawes *Figen veeture.Soivihg the个Ka (K2-Xx)I= Edentiy mounix =LCF Dynamic mamux [m'K]Inlmamim] => ml= adj mmima%3Dmi1)m2K+K2- K2KitkaK2miIC]= [m] K] =%3D-K2K2K2mam2Then-K22-KitkzmimiK2K2m2K2K2K2> (a - KitkamiM2M22.K22(kitk2),Ke (Kitkz)mim2mamiK2m2K2KamaKitK2mimlIwotIBy soiving tue egnSolvingwe find theK = m,2,m1うKa = m, 12m2 (4.31 x 10Advanced Research in Natural Fibers, Vol. 2 No. 1 (2020) p. 15-20First iteration.Given (X)trielHTherefore [K]|M] {X} = {Xnew}Isolator pad2.66 X 10-The Largest (X) = 2.66 x 10-4Nomalized (X)newholator padFigureFigureY1.Fig. 1- Stackable washing and dryer machine andits two DOFS mass spring system[2.66 x 10-412.66 x 10-412.66 × 10-4)- HSecond iteration.Given (X)triat =ITherefore (K]|M] {X} = {Xnew}%3D15.97 >The Largest {Xew) = 5.97 x 10-4Nomalized (X}newFig. 2- Free body diagram of stackable washing anddryer machine[4.31 x 10-45.97 x 10-415.97 x 10-4]After the free body diagram (refer Fig. 2) show all the relateddirection and force applied, an equation of motion can bederived as follows.M,X, – k2x2 + (k2 + k,)x, = 0M2X2 - k2x1 + k2x2 =05. Based on the above iteration, after multiply [K]-'|M] {X}- {Xnew), the (Xnew} can be normalized by using the largestXpew[k, +k2-k2k26. Then, check the converge and use for a new trial {Xaew}.7. The calculation of {Xnew} is repeated until the largest Xmewbecome constant where is the 7" iteration.Then, the lowest natural frequency for both Neoprene andSorbothone materials using matrix iteration method.1. Identify matrix [K] & [M]8. Lastly, the lowest natural frequency is calculated by usingthe formula given:|M]= [93 01lo 58l1[K]-[ 700000l-350000 350000-3500001Xnormalized2. To find the lowest natural frequency, turn [K] to [K]5.11 x 10-4= 44.24 rad/s[K]-1 = 2.86 x 10-6 2.86 x 10-612.86 x 10-6 5.71 x 10-62.2 Validation codingThe Mathlab coding used to find the lowest naturalfrequency is shown as follows:3. Define the initial trial vector as:{X} -n-input ('Enter dimension of the matrix, n:A - zeros (n, n) ;x - zeros (1,n);y - zeros (1, n) :tol - input ('Enter the tolerance, tol: '):m - input ('Enter maximum number of iterations,');4. Multiply [K]-1|M] {X} = {Xnew}[K]-'|M]-|2.66 x 10- 1.66 x 10-*12.66 x 10- 3.31 x 10-)m:17Published by FAZ Publishinghttp://www.fazpublishing.com/arnf

k=k1+k2-k2-k2k2 (1) given: k=700000-350000-350000350000 (2)

Answered: From the matrix can you show me how the…

Engineering

Mechanical Engineering

From the matrix can you show me how the value stiffness (k) calculated?

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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