Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)₂(aq) + 2 NHÂI(aq) → PbL₂(s) + 2 NH₂NO3(aq) What volume of a 0.350 M NH4I solution is required to react with 257 mL of a 0.180 M Pb(NO3)2 solution? volume: How many moles of Pbl2 are formed from this reaction? moles: mL mol Pbl2

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Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction
Pb(NO3)₂(aq) + 2NH₂I(aq) →→→ PbL₂(s) + 2NH4NO3(aq)
What volume of a 0.350 M NH4I solution is required to react with 257 mL of a 0.180 M Pb(NO3)2 solution?
volume:
How many moles of Pbl2 are formed from this reaction?
moles:
mL
mol Pbl2
Transcribed Image Text:Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)₂(aq) + 2NH₂I(aq) →→→ PbL₂(s) + 2NH4NO3(aq) What volume of a 0.350 M NH4I solution is required to react with 257 mL of a 0.180 M Pb(NO3)2 solution? volume: How many moles of Pbl2 are formed from this reaction? moles: mL mol Pbl2
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