Calculate the number of milliliters of 0.479 M Ba(OH)₂ required to precipitate all of the Cr³+ ions in 156 mL of 0.725 M CrIs solution as Cr(OH)3. The equation for the reaction is: 2Crls (aq) + 3Ba(OH)2 (aq) → 2Cr(OH), (s) + 3Bal₂ (aq) ml Volume= Submit Answer Retry Entire Group 9 more group attempts remaining

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Calculate the number of milliliters of 0.479 M Ba(OH)2 required to precipitate all of the Cr³+ ions in 156 mL of 0.725 M CrIs solution as
Cr(OH)3. The equation for the reaction is:
2Crls (aq) + 3Ba(OH)2 (aq) → 2Cr(OH)s (8) + 3Bal, (aq)
ml.
Volume=
Submit Answer
Retry Entire Group 9 more group attempts remaining
Transcribed Image Text:Calculate the number of milliliters of 0.479 M Ba(OH)2 required to precipitate all of the Cr³+ ions in 156 mL of 0.725 M CrIs solution as Cr(OH)3. The equation for the reaction is: 2Crls (aq) + 3Ba(OH)2 (aq) → 2Cr(OH)s (8) + 3Bal, (aq) ml. Volume= Submit Answer Retry Entire Group 9 more group attempts remaining
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