Chemistry by OpenStax (2015-05-04)
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ISBN: 9781938168390
Author: Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher: OpenStax
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Kw at 0K is 2.00E-01. What is the [H3O+]?
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- Find delta Harrow_forwardCalculate the AG° (in kJ/mol H2O2) for the reaction below: 2 H2O2 (aq) → 02 (e) + 2 H2O (1) AG°F H2O2 (aq) = -134.1 kJ/mol %3D AG°F H2O (1) = -237.2 kJ/mol IMPORTANT: When entering your answer: •Enter the number only (no units) • Do not leave any spaces • Include the sign if your answer is negative (not necessary for positive values) • Use a leading zero before the decimal when necessary • Report your number to 1 decimal place (regardless of the significant figures) Correctly round your answer to the 1st decimal place (margin of allowed error is only + 0.1, so always use un-rounded numbers in your calculations). If the last digits are zeros they will not display once you click away, but the answer will still be marked correct. Examples: 12.3 or -0.4arrow_forwardQUESTIONS FOR RESEARCH 1. Discuss the nature (organic, acids, bases, heavy metals) of AgNO3, NaOH, CH₂COOH, CH3CH₂OH and heat. COME |||₁arrow_forward
- Determine the AH of the reaction 1 1 NO29) + 702c9) +5H20(9) → HNO3(aq) 4 AH = 33.2 kJ 5 N2c9) + O2cg) → N02c9) 1 Haa) +Nzo) +0zc) → HNO3(aq) AH = -202.3 kJ 1 H2(g) - ΗΝO3(αq) 1 H2(g) * 2 → H20(g) AH = -285.8 kJarrow_forwardCalculate AH for the following reaction, given the data in the table below: 4N204 (2) →2N20g) + 4NO2 (g) + 302 AH = ??? kJ/mol 2NO2 (e) + 2NO() +O2 (g)→2N2O4 (g) AH = -396.81 kJ 4NO+ 2N2Og) + 502 (g)→4N2O4 (g) AH = -398.88 kJ 2NO + O2 ()→N2O4 (3) AH = -173.09 kJarrow_forward[References] Calculate AH for the reaction: 2NH3 (g) + O2(g) → N2H4 (1) + H2O(1) given the following data: 2NH3 (g) + 3N2O(g) → 4N2(g) + 3H2O(1) AH =–1010. kJ N2O(9) + ЗH2(9) — N;Ha (1) + Hа0(1) ДН %3D — 317 kJ N2H4 (1) + O2 (9) → N2(g)+2H20(1) ΔΗ--623 k.J На (9) + О2(9) — Н,0(1) AH = -286 kJ ΔΗ- kJ Submit Answer Try Another Version 3 item attempts remainingarrow_forward
- Calculate ΔΗ.for Cats) + % O2(e) + Given the following set of reactions: Cais) + CaCO3(s) > CO2 (8) CaCO3(5) ½ O2le) → CaO(s) CO 21g) AH = -635.1 kJ AH = 178.3 Kj CaO(s) + wwww O -813.4 kJ 813.41 kJ O.-456.8 kJ 456.8 kJarrow_forwardFf.316.arrow_forwarda) Calculate AH, for the reaction H3PO4 (aq, r = ∞) + 3NaOH(aq, r = 50) → Na3PO(aq, r = ∞) + 3H₂O(l) b) If 5.00 mol of NaOH dissolved in 250 ml water is neutralised completely at 25°C with dilute phospohoric acid (H₂PO4), what is the enthalpy change? (AĤ;) NaOH(s) = -426.6 kJ mol-¹ |\¼Ã³NaOH(r = 50) = −42.51 kJ mol-¹ (AĤƒ) H₂PO4(ªq) = -1294 kJ mol-¹ (AA). = -285.8 kJ mol-¹ H₂0 (1) (f) Na3PO4 (aq) = -1974 kJ mol-¹arrow_forward
- Calculate AH for the reaction: 2NH3 (g) + O2(g) → N2H4 (1) + H2O(1) given the following data: 2NH3 (g) + 3N20(g) → 4N2(g) + 3H2O(1) AH = –1010. kJ N20(g) + 3H2 (9) → N¿H4(1)+H2O(1) AH = -317 kJ N2H4 (1) + O2 (g) → N2(g)+ 2H2O(1) AH = -623 kJ H2 (9) + 02 (9) → H2O(1) AH = -286 kJ ΔΗ - kJarrow_forwardCalculate AH for the following reaction, given the data in the table below: H2SO4() → So:(g) + H2O(g) AH = ??? kJ/mol H2S(g) +202(g)→ H2SO4(1) AH = -749.7 kJ H,S(g) + 202(g) → SO3(g) + H2O(1) AH = -355.0 kJ H20(1) H20(g) AH = +53.95 kJarrow_forwardThe molecule shown below is oxidized with KMNO4 at elevated temperatures. Which product A to D is formed? Click on a letter A to D to answer. KMNO4 60 °C, H2O NaOH HO2C CO,H A B HO,C HO,C cO,H Darrow_forward
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