Knight P6.67 A 70 kg cyclist is coasting down a long hill that has a 5° slope. His cross-section area is 0.35 m², his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is r = 0.02, and the density of air is 1.2 kg/m³. What speed does he eventually reach? 5⁰ y FN W Farag Ffriction X
Knight P6.67 A 70 kg cyclist is coasting down a long hill that has a 5° slope. His cross-section area is 0.35 m², his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is r = 0.02, and the density of air is 1.2 kg/m³. What speed does he eventually reach? 5⁰ y FN W Farag Ffriction X
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![3. Knight P6.67 A 70 kg cyclist is coasting down a
long hill that has a 5° slope. His cross-section area
is 0.35 m², his drag coefficient is 0.85, his bicycle's
coefficient of rolling friction is r = 0.02, and the
density of air is 1.2 kg/m³. What speed does he
eventually reach?
5⁰
y
FN
W
Farag
Ffriction
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F760b950f-bf86-4f0e-8f61-09da7fb76390%2F88530547-f508-470b-aef5-00060b2e220d%2F6e7r24s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Knight P6.67 A 70 kg cyclist is coasting down a
long hill that has a 5° slope. His cross-section area
is 0.35 m², his drag coefficient is 0.85, his bicycle's
coefficient of rolling friction is r = 0.02, and the
density of air is 1.2 kg/m³. What speed does he
eventually reach?
5⁰
y
FN
W
Farag
Ffriction
X
![Useful information
Newton's 2nd law component form
ΣΕ = max
X
ΣFy = may
Static, kinetic, and rolling friction
Quadratic drag
F, < μgFN
Fk = μk FN
Fr=r FN
F₁ = CpAv²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F760b950f-bf86-4f0e-8f61-09da7fb76390%2F88530547-f508-470b-aef5-00060b2e220d%2Ffosoxw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Useful information
Newton's 2nd law component form
ΣΕ = max
X
ΣFy = may
Static, kinetic, and rolling friction
Quadratic drag
F, < μgFN
Fk = μk FN
Fr=r FN
F₁ = CpAv²
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