Keq for the reaction 2 NO2 (g) N204 (g) is 4.73. If a container holds 2.10 M N2O4 and 0.0887 M NO2 and is allowed to come to equilibrium, which of the following would be the BEST set-up to solve for the concentration of NO2 at equilibrium? NO2 N204 I: 0.0887 2.10 C: +2X - 1X E: 0.0887 + 2X 2.10 - 1X NO2 N204 1: 0.0887 2.10 C: - 2X + 1X E: 0.0887 2X 2.10 +1X NO2 N204 I: 0.0887 C: - 2 X E: 0.0887- 2X 2.10 +1X NO2 N204 : 0.0887 2.10 C: +1X 1X E: 0.0887 + 1X 2.10 2X NO2 N204 I: 0.0887 2.10 C: + 1X 2X E: 0.0887 + 1X 2.10 - 1X

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Keq for the reaction 2 NO2 (g) N204 (g) is 4.73. If a container holds 2.10 M N204 and
0.0887 M NO2 and is allowed to come to equilibrium, which of the following would be the
BEST set-up to solve for the concentration of NO2 at equilibrium?
O NO2
N204
I:
0.0887
2.10
C: +2X
- 1X
E: 0.0887 + 2X
2.10 1X
NO2
N204
11
11
I:
0.0887
2.10
%3D
C: -2X
+1X
E:
0.0887 - 2X
2.10 +1X
NO2
N204
I:
0.0887
C: - 2X
+X
E:
0.0887 - 2X
2.10 +1X
NO2
N204
I:
0.0887
2.10
C: +1X
1X
E:
0.0887 + 1X
2.10 2X
NO2
N204
:
0.0887
2.10
C:
+ 1X
2X
E:
0.0887 + 1X
2.10 - 1X
Transcribed Image Text:Keq for the reaction 2 NO2 (g) N204 (g) is 4.73. If a container holds 2.10 M N204 and 0.0887 M NO2 and is allowed to come to equilibrium, which of the following would be the BEST set-up to solve for the concentration of NO2 at equilibrium? O NO2 N204 I: 0.0887 2.10 C: +2X - 1X E: 0.0887 + 2X 2.10 1X NO2 N204 11 11 I: 0.0887 2.10 %3D C: -2X +1X E: 0.0887 - 2X 2.10 +1X NO2 N204 I: 0.0887 C: - 2X +X E: 0.0887 - 2X 2.10 +1X NO2 N204 I: 0.0887 2.10 C: +1X 1X E: 0.0887 + 1X 2.10 2X NO2 N204 : 0.0887 2.10 C: + 1X 2X E: 0.0887 + 1X 2.10 - 1X
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