J-Find the rise in a tube capillary * shown for a water- glass interface e=0 iF the tube radius is Imm and the density is 1000kg Im?. Sur face tensian of water is 0.0728 N m.
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Q: The capillary rise (height) in mm of a water having a viscosity of 0.0728 J/m2. The tube has a…
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Q: 3000 psi, n= 9, M= 70 ft-k.
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A: 1 m = 1000 mm cos0=1
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Q: The radius of the tube is 1.3 mm. The surface tension of water at 20°C is equal to 0.0728 N/…
A: Given: Raduis of tube Surface tension Angle To find: Capillary rise
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Q: Compute the capillary rise in mm of pure water at 10 Celsius expected in an 0.8 mm diameter tube.
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Q: 2) the total Pressure on the base of the tunk2 the Pressuye on the Vertical siis of the tank?
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Q: redfus af the tube (8) = 2 mm = 2X10m Surface tenston ()= 0.752N/m %3D wetting angle 10) = 130 To…
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Q: Find the capillary rise ( h) in the tube shown in the figure for a water-air-glass interface with 9=…
A: Answer = 25.544 mm
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Q: Required information The tube shown has a uniform wall thickness of 12 mm. Take P= 19 kN.
A: Calculate the direct stresses as follows:
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- The aluminum tube AB of cross section has a fixed support on the base and is supported by a pin at the top of a horizontal beam supporting a load Q = 200 kN. Determine the required thickness t of the tube if its outside diameter for 100 mm and the necessary safety factor in relation to Euler buckling for n = 3.0 (assuming A = 72 GPa).A high-density polyethylene [E = 135 ksi and a = 69 x 10-6/°F) block (1) is positioned in a fixture. The block is 2.1 in, by 2.2 in. by 36 in. long. At room temperature, a gap of 0.1 in. exists between the block and the rigid support at B. Assume L₁- 36 in and A = 0.1 in. Determine: (a) the normal stressa in block (1) caused by a temperature increase of 70°F. (b) the normal strain e in block (1) at the increased temperature. Answers: (a) a = (b) = i B 277.05 A LA psi. pc.A spherical stainless-steel tank having an inner diameter ‘D’, is used to store naturalgas at a pressure of ‘p’. The properties of the steel are as follows: yield stress in tensionis ‘T’; yield stress in shear is ‘S’ and modulus of elasticity is ‘E’. The desired factor ofsafety with respect to yielding is ‘F.S’.Determine the minimum permissible thickness t min of the tank. (D (mm)=620)( p (MPa)=25)( T (MPa)=1000)( S (MPa)=440)( E (GPa)=208)( F.S=3.4)
- The block shown is made of a magnesium alloy for which E=X2GPaand ϑ=0.35. Knowing that σx= X1 MPa, determine (a) the magnitude of σyfor which the change in the height of the block will be zero, (b) the corresponding change in the area of the face ABCD, (c) the corresponding change in the volume of the block.The radius of the tube as shown in the figure is 1 mm. The surface tension of water at 20 deg C is equal to 0.0728 N/m. For a water-glass interface 0 = 0 Compute the total force due to surface tension in Newton h 2r-2. A rod is composed of an aluminum section rigidly attached between steel and bronze sections as shown in the figure. Axial loads are applied at the positions indicated. The cross-sectional area of the rod is 300sq.mm. Express your answer in MPa. Determine the stress in the steel. b. a. Determine the stress in the aluminum. Determine the stress in the bronze. C. STEEL ALUMINUM BRONZE 56kN 14kN -0.6m- -0.9m- -0.76m-
- A rod is composed of copper and steel section rigidly bolted in the wall as shown in the figure. If an axial load of F = 300 N and the cross sectional area of the rod is 200 mm2 , determine the stress in the section of copper. ... Сopper Steel 2F F 3m 2m A) 1.5 MPa В 0.75 MPa 3.0 MPа D 4.5 MPa5. A steel bolt through a 25-in long aluminum tube has the nut turned on until it just touches the end of the tube. No stress is introduced on the bolt or the tube. The temperature of the assembly is raised from 70 to 79 degrees Fahrenheit. The cross- sectional area of the bolt is 0.08 sq. inch and the cross-sectional area of the tube of 0.25 sq. inch. For steel: E = 30 x 106 psi, coefficient of thermal expansion = 6.5 x 10-6/°F For aluminum: E = 10 x 106 psi, coefficient of thermal expansion = 13.0 x 10-6/°F a. Find the thermal deformation (in inches) of the bolt. b. Find the thermal deformation (in inches) of the aluminum tube. c. Find the stress (in psi) induced in the bolt by the temperature change. d. Find the stress (in psi) induced in the aluminum tube by the temperature change.The brass strip AB has been attached to a fixed support at A and rests on a rough support at B. Knowing that the coefficient of friction is 0.60 between the strip and the support at B, determine the decrease in temperature for which slipping will impend.
- P.E. Pressure -a.) Find the bulk modulus of elasticity of a liquid if a pressure of 150 psi applied to 10 ft3 of the liquid causes a volume reduction of 0.02 ft.3. b.) Find the capillary rise in the tube for a water-air-glass interface (θ = 0°) if the tube radius is 1 mm. Surface tension is 0.0728 N/m.Q8: Consider a steel rod of fixed ends. If the temperature of the rod is increased by AT-80 °C, then the generated thermal stress (in MPa) in the rod is: (Hint: For the steel, the Young's modulus (Y) is 2x10 N/m and the coefficient of linear thermal expansion (a) is 11 x 106 ly a) 2.2 b) 176.0 c) 352 d) 776.6