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It is found that up to 0.0110 g of SrF2 dissolves in 100 mL of aqueous solution at a certain temperature. Determine the value of Ksp for SRF2. 2 NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. SrF2(s) Sr2* (aq) 2 F(aq) + Initial (M) 8.76 x 10-4 Change (M) -8.76 x 10-4 +2x +x Equilibrium (M) +2x +x 2 RESET

It is found that up to 0.0110 g of SrF2 dissolves in 100 mL of aqueous solution at a certain temperature. Determine the value of Ksp for SRF2. 2 NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. SrF2(s) Sr2* (aq) 2 F(aq) + Initial (M) 8.76 x 10-4 Change (M) -8.76 x 10-4 +2x +x Equilibrium (M) +2x +x 2 RESET

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.81QE: Use the solubility product constant from Appendix F to determine whether a precipitate will form if...
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It is found that up to 0.0110 g of SrF2 dissolves in 100 mL of aqueous solution at a certain temperature. Determine the value Ksp for SrF2. 1 2 NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. SFF2(s) Sr**(aq) 2 F (aq) + Initial (M) 8.76 x 10-4 Change (M) -8.76 x 10-4 +2x +x Equilibrium (M) +2x +x 5 RESET 0.0110 8.76 x 10-5 8.76 x 10-4 1.75 x 10-4 1.75 x 103 -0.0110 -8.76 x 10-5 -8.76 x 10-4 -1.75 x 10-4 -1.75 x 103 +x +2x -2x -X 8.76 x 10-5 + x 8.76 x 10-5 - x 1.75 x 10-4 + 2x 1.75 x 10-4 - 2x 1L
Transcribed Image Text:It is found that up to 0.0110 g of SrF2 dissolves in 100 mL of aqueous solution at a certain temperature. Determine the value Ksp for SrF2. 1 2 NEXT > Based on the given values, fill in the ICE table to determine concentrations of all reactants and products. SFF2(s) Sr**(aq) 2 F (aq) + Initial (M) 8.76 x 10-4 Change (M) -8.76 x 10-4 +2x +x Equilibrium (M) +2x +x 5 RESET 0.0110 8.76 x 10-5 8.76 x 10-4 1.75 x 10-4 1.75 x 103 -0.0110 -8.76 x 10-5 -8.76 x 10-4 -1.75 x 10-4 -1.75 x 103 +x +2x -2x -X 8.76 x 10-5 + x 8.76 x 10-5 - x 1.75 x 10-4 + 2x 1.75 x 10-4 - 2x 1L
It is found that up to 0.0110 g of SrF2 dissolves in 100 mL of aqueous solution at a certain temperature. Determine the value of Ksp for SrF2. ( PREV 1 2 Based on the set up of your ICE table, construct the expression for Ksp and then evaluate it. Do not combine or simplify terms. Ksp [8.76 x 10-41 [1.75 × 10]? 2.68 x 10-9 %3D %3D RESET [0] [0.0110] [8.76 х 10-5] [8.76 х 10-4] [1.75 x 10-4] [1.75 х 10"3] [0.0110]? [8.76 x 10-sp [8.76 x 10-4p [1.75 х 10-4 [1.75 х 10-3)2 [x] [2x]? [8.76 x 10-5 + x] [8.76 x 10-5 - x] [1.75 x 10-4 + 2x]? [1.75 x 10-4 - 2x]? 2.68 x 10-9 1.53 x 10-6 2.68 x 10-12
Transcribed Image Text:It is found that up to 0.0110 g of SrF2 dissolves in 100 mL of aqueous solution at a certain temperature. Determine the value of Ksp for SrF2. ( PREV 1 2 Based on the set up of your ICE table, construct the expression for Ksp and then evaluate it. Do not combine or simplify terms. Ksp [8.76 x 10-41 [1.75 × 10]? 2.68 x 10-9 %3D %3D RESET [0] [0.0110] [8.76 х 10-5] [8.76 х 10-4] [1.75 x 10-4] [1.75 х 10"3] [0.0110]? [8.76 x 10-sp [8.76 x 10-4p [1.75 х 10-4 [1.75 х 10-3)2 [x] [2x]? [8.76 x 10-5 + x] [8.76 x 10-5 - x] [1.75 x 10-4 + 2x]? [1.75 x 10-4 - 2x]? 2.68 x 10-9 1.53 x 10-6 2.68 x 10-12
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