2NO(g) + O₂(g) = 2NO₂(g) K = 1.5 x 10-10 The current concentrations for the system are given below. What is the reaction quotient, Q, for the system? [NO] = 0.52 M [0₂] = 0.351 M [NO₂] = 0.133 M Q = [?] Reaction Quotient Enter

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### Reaction Quotient Calculation

**Chemical Reaction:**
\[ 2\text{NO} (g) + \text{O}_2 (g) \rightleftharpoons 2\text{NO}_2 (g) \]
**Equilibrium Constant (K):** \[ 1.5 \times 10^{-10} \]

**Problem Statement:**
The current concentrations for the system are given below. What is the reaction quotient, Q, for the system?

**Given Concentrations:**
\[ [\text{NO}] = 0.52 \, M \]
\[ [\text{O}_2] = 0.351 \, M \]
\[ [\text{NO}_2] = 0.133 \, M \]

**Calculation of Reaction Quotient, Q:**

The reaction quotient (Q) is calculated using the following formula corresponding to the balanced chemical equation:

\[ Q = \frac{[\text{NO}_2]^2}{[\text{NO}]^2 [\text{O}_2]} \]

**Instructions for Calculation:**

1. Substitute the given concentrations into the formula:
   \[ Q = \frac{(0.133)^2}{(0.52)^2 \times 0.351} \]
2. Perform the necessary arithmetic to find the value of Q.

**Interactive Element:**
- There is an input box labeled "Reaction Quotient" where users can enter their calculated value of Q.
- Upon entering their value, users can press the "Enter" button to check their answer.

**Note:** The exact result of the calculation is not provided here as this transcription assumes the role of a teaching resource where users are expected to perform the calculation themselves for practice.
Transcribed Image Text:### Reaction Quotient Calculation **Chemical Reaction:** \[ 2\text{NO} (g) + \text{O}_2 (g) \rightleftharpoons 2\text{NO}_2 (g) \] **Equilibrium Constant (K):** \[ 1.5 \times 10^{-10} \] **Problem Statement:** The current concentrations for the system are given below. What is the reaction quotient, Q, for the system? **Given Concentrations:** \[ [\text{NO}] = 0.52 \, M \] \[ [\text{O}_2] = 0.351 \, M \] \[ [\text{NO}_2] = 0.133 \, M \] **Calculation of Reaction Quotient, Q:** The reaction quotient (Q) is calculated using the following formula corresponding to the balanced chemical equation: \[ Q = \frac{[\text{NO}_2]^2}{[\text{NO}]^2 [\text{O}_2]} \] **Instructions for Calculation:** 1. Substitute the given concentrations into the formula: \[ Q = \frac{(0.133)^2}{(0.52)^2 \times 0.351} \] 2. Perform the necessary arithmetic to find the value of Q. **Interactive Element:** - There is an input box labeled "Reaction Quotient" where users can enter their calculated value of Q. - Upon entering their value, users can press the "Enter" button to check their answer. **Note:** The exact result of the calculation is not provided here as this transcription assumes the role of a teaching resource where users are expected to perform the calculation themselves for practice.
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