It is desired to run a bank of ten 100-W, 10-V lamps in parallel from a 230-V, 50-Hz supply by inserting a choke coil in series with the bank of lamps. If the choke coil has a power factor of 0.2, find its resistance, reactance and inductance.
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- Q5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across Ri, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) D1 IN4001 R. V out OV 10 kN D2 IN4001 llleQ5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across Ri, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) D1 IN4001 RL out OV 10 kN IN4001 alllQ5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across R, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) D IN4001 R 10 kn IN4001
- Design a half-wave rectifier fed from 224-V line through a step-up transformer (5:8). The load requires an average voltage of 24 V and average power of 8 W. Use 15% safety factor. Summarize answers on the space provided. *A snubber circuit has snubber time constant (10 msec), voltage source (10 kV), discharge current of the Thyristor (5 µA) and frequency (50 Hz). Find the rate of voltage changing with time and snubber circuit power losses?Design a DC power supply using FWR to perform the following requirements. Find V_dc, V_rms, V-ripple, PIV of the diode. draw the waveform of (V_in, V_out, L_in, I_load, V_diode and I_diode). Input voltage = 25 Transformer turn ratio 0.1 load resistance = 1k ohm Ripple factor = 0.025 Diode type =Si
- Q1-Determine the ripple factor (r) for the filtered rectifier with a load as indicated in the figure below.What are the main benefits of using the transformer in this circuit? * 1 :1 D, Vims =130v Vpi pri ) VpMsec) f= 50 HZ RL D4 100 uF D2 2kaAn AC ammeter is connected in series with the primary winding of T1. What is the expected current reading? An AC ammeter is connected in series with the secondary winding of T1. What is the expected current reading? An AC ammeter is connected in series with R1. What is the expected current reading? NOTE: Idc for HW rectifier = 0.318 * Ipeak = 0.45 * Irms Describe/Explain briefly the purpose/use of the array (series-parallel) connection of the rectifier diodes in the given circuit.10. A potential difference of 250 V is applied to a field winding at 15-C and the current is 5 A. What will be the temperature of the winding when current has fallen to 3.91 A applied voltage being constant. Assume temperature coefficient at 15'C is equal to 1/254.5 per °C
- A single phase full converter feeds power to RLE load with R=10 ohm, L=10 mH and E=50 V, the ac source voltage is 230 V, 50 Hz. For continuous conduction, what is the average value of load current for firing angle delay of 600 ?Each terminal of a small polarity-independent incandescent bulb is connected to the positive terminals of two (2) DC voltage sources. The negative terminals of these sources are connected together. The first voltage source can have a range of value from 0-12, incrementable by 1.5 volts every turn of the rotary switch (i.e. 0 V, 1.5 V, 3 V, 4.5 V .... 12 V). The voltage of the second source is unknown. Using a luxmeter, the brightness of the lamp was measured for every increment of voltage of the first source. The following observations were recorded: a. 1.5 V produces a higher brightness than 3 V b. 0 V produces a higher brightness than 1.5 V c. 12 V produces higher brightness than 9 V d. 12 V produces equal brightness as 3 V What is the voltage of the second source? Justify each observation.Untitled Section Jalis 6 In d.c. generators armature reaction is produced by field current O armature current commutating winding current none of the mentioned compensating winding current *.The use of d.c. generators eliminated the use of rectifiers and ac supplies True False O