It is claimed that the proportion of OSU students who belong to a fraternity or a sorority is 0.15. A college administrator has some reason to question this claim, and she gathers data from a random sample of 200 students in order to test Ho: p = 0.15 against Ha: p ≠ 0.15.  If the resulting test statistic is 0.9, what will the P-value be?   0.8159 0.1841 0.0180 0.0090 0.3682

According to the College Board, scores on the math section of the SAT Reasoning college entrance test for the class of 2010 had a mean of 516 and a standard deviation of 116. Assume that they are roughly normal.One of the quartiles of the scores from the math section of the SAT Reasoning test is 438. The other quartile is _______.

The recidivism rate for convicted sex offenders is 9%. A warden suspects that this percent is higher if the sex offender is also a drug addict. Of the 396 convicted sex offenders who were also drug addicts, 51 of them became repeat offenders. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Но: 0.09 |(please enter a decimal) H1: P 0.09 (Please enter a decimal) c. The test statistic ? 2.697 (please show your answer to 3 decimal places.) d. The p-value =| 0.0035 v (Please show your answer to 4 decimal places.) e. The p-value is f. Based on this, we should reject the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton proportion is significantly higher than 9% at a = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat…

In a random sample of   925   plain​ M&M's, 19% were blue. Use a 0.01 significance level to test the claim of​ Mars, Inc. that​ 24% of its plain​ M&M candies are blue. a. Define the parameter     A. p​ = The proportion of all​ M&M's that are blue   B. mu   ​= The proportion of all​ M&M's that are blue   C. mu   ​= The mean number of all​ M&M's that are blue   D. p​ = The proportion of all​ M&M's that are not blue   b. State the null and alternative hypotheses     A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24     B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19     C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24     D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24     c. Calculate the test statistic. Which of these options is closest to the test​ statistic?     A. negative 4.00     B. negative 3.65     C.…

Question 3 According to a Kaiser Family Foundation survey, children aged 8 to 18 years in the United States spend an average of 190 minutes per day watching television. A recent random sample of 4 such children showed the following results: 200, 210, 230, 220 (in minutes) At the 5% level of significance, can you conclude that the current mean time spent watching television per day by children in this age group differs from 190 minutes? a)Step 1: State the null and alternative hypotheses. b)Step 2: Write down the appropriate test statistic (formula) , but first check assumptions c) Step 3 :Write down the rejection region of your test. d)Step 4: Compute the value of the test statistic (i) The sample mean = The sample standard deviation = (iii) The value of the test statistic = e) Step 5: State your conclusion: (i) Reject Ho Do not reject Ho (Just circle) (ii) In one sentence apply the results to the problem. f)What type of mistake could you have made in your hypothesis test? (Just circle…

Find the​ range, variance, and standard deviation for the given sample​ data, if possible. If the measures of variation can be obtained for these​ values, do the results make​ sense? Biologists conducted experiments to determine whether a deficiency of carbon dioxide in the soil affects the phenotypes of peas. Listed below are the phenotype​ codes, where 1 equals ​smooth-yellow, 2 equals ​smooth-green, 3 equals wrinkled ​yellow, and 4 equals ​wrinkled-green.   a. The range of the sample data is ​(Type an integer or a decimal. Do not​ round.)   b. the standard deviation of the sample data is ​(Round to one decimal place as​ needed.)   c. The variance of the sample data is ​(Round to one decimal place as​ needed.)

Consider the following 3 independent sample statistics (from Exercise 11.2.1, pg 454): Sample 1: Mean=43, SD=3.74, n=4, Sample 2: Mean=44, SD=4, n=3, Sample 3: Mean=34, SD=3.92, n=4. Compute the SS(between) and the SS(within).    Type the three digit numbers, first representing the SS(between) and second the SS(within), separated by comma with no spaces; e.g., 350,278 SHOW THE STEPS I NEED A NEW ANSWER PLEASE

You wish to test the following daim (Ha) at a significance level of a = 0.001. H.:P1 2 P2 Ha:P1 < P2 You obtain a sample from the first population with 244 successes and 117 failures. You obtain a sample from the second population with 523 successes and 202 failures. test statistic = [three decimal accuracy] p-value = [four decimal accuracy) The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null hypothesis O fail to reject the null hypothesis As such, the final condusion is that... O There is sufficient evidence to support that the first population proportion is less than the second population proportion. There is not sufficient evidence to support that the first population proportion is less than the second population proportion.

Consider the data from the Anthropology 105 class.  The mean for women is 64.33 in and the standard deviation is 2.64 in. The average height of men in the US is approximately 5ft 10in. What proportion of women represented here are shorter than the average man?

Children with autism differ significantly from children without autism on tests of varbal ability.   repeated measures? or ind. with two tails?