College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Calculate the final speed vs of a 2.00-kg object that is pushed 2.00 kg for 34.0 m by a 30.0-N force directed 30.0° below the 30° horizontal on a level, frictionless floor, as shown in the figure. Assume the object starts from rest. d Uf = m/sarrow_forwardA net external force is applied to a 25-kg object that is initially moving at 1 m/s. The net force component along the displacement of the object varies with the magnitude of the displacement as shown in the drawing. What is the final KE (in Joules) of the object at x=20m? What is the speed (in m/s) of the object at x=20m?arrow_forwardShown below is a graph of the 1-dimensional force FYP,x(x), that you exert on a particle of mass 12 kg. The point 0,0 is in the lower-left corner. Each vertical grid line is 1 N, and each horizontal grid line is 1 m. The particle starts at x=4 m with a velocity of 8.73 m/s and reaches x=24 m under the action of only the force in the graph, i.e. the force shown is the net force. What is the x component of the impulse that you give to the particle as it moves from x=4 m until it reaches x=24 m? Remember that impulse is a vector, so you will need to take into account directions. In particular, you will need to determine whether or not the particle turns around. Because impulse is a vector, in 1 dimension it can be either positive or negative.arrow_forward
- A glider of mass 0.275kg is placed at rest on an air track that has an angle of inclination of 10°. The height of the glider above the table is 30cm. The glider is released traveling 1.15m down along the track. When the glider is at 10cm above the height of the table, the velocity is 1.5m/s. What is the frictional force acting on the glider?arrow_forwardProblem 4 (Figure B). A mass of 2 kg is projected with a speed of 3 m/s up a plan inclined 20° with the horizonal. After traveling 0.8 m, the mas comes to rest. (a) Determine the coefficient of kinetic friction. (b) Determine the speed of the block when it returns to i starting position. Draw 2 x 9.8 19.6 N 20° N Figure B "Narrow_forwardShown below is a graph of the 1-dimensional force FYP, (x), that you exert on a particle of mass 12 kg. The point 0, 0 is in the lower-left corner. Each vertical grid line is 1 N, and each horizontal grid line is 1 m. The particle starts at x = 4 m with a velocity of 7.86 m/s and reaches x = 24 m under the action of only the force in the graph, i.e. the force shown is the net force. Work What is the work done on the particle by the force from x = 4 m to x = 24 m? W = Particle Speed Λ What is the speed of the particle when it reaches a 24 m? Vx Impulse of You on Particle Λ What is the x component of the impulse that you give to the particle as it moves from x = 4 m until it reaches x = 24 m? Remember that impulse is a vector, so you will need to take into account directions. In particular, you will need to determine whether or not the particle turns around. Because impulse is a vector, in 1 dimension it can be either positive or negative. Iym,x Impulse of Particle on You What is the x…arrow_forward
- Particle A has mass m. Particle B has twice the mass of Particle A. The same constant force F acts on both particles over distance Ax. Which particle has the larger kinetic energy? O EA > EB EA < EB EA = EB There is not enough information to tell.arrow_forwardShown below is a graph of the 1-dimensional force FYP,x(x), that you exert on a particle of mass 8 kg. The point 0,0 is in the lower-left corner. Each vertical grid line is 1 N, and each horizontal grid line is 1 m. The particle starts at x=4 m with a velocity of 12.19 m/s and reaches x=22 m under the action of only the force in the graph, i.e. the force shown is the net force. What is the speed of the particle when it reaches x=22?arrow_forwardA 02 UBC Engineering A trapeze artist of a mass of M to 01 trick. If the ropes do NO work on the artist, what is the speed just before they let go? What is their normal acceleration? 79kg is attempting a new trick on a rope of l 70° and then rope A is cut. The artist holds on until when 02 = 15° then lets go for the next 15m. They are lifted Neglect size and air resistancearrow_forward
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