A block of mass m = 7 kg rests on a horizontal surface with che following coefficients of static and kinetic friction: Hs = 0.5 Hk = 0,2 A force F is applied to the block at an angle 0 = 55° with respect to the horizontal. See Figure 4. Suppose the applied orce has magnitude F = 60 N. This force is adequate to move the block. If the block is initially at rest, calculate the speed of the block after it has moved a distance d = 13 m. Note that the applied force is applied continuously throughout this distance. Figure 4

A body with a mass of 4.71 kg moves along the x-axis, influenced by a conservative force F (x). F(x) = Ax's N A =-4 m3 where When the body is at position x, = 2.05 m, it is moving with a speed of v, 6.01 m/s. What is the body's speed when it is at position xf -2.55 m? speed: m/s

Use energy conservation to find the approximate final speed of a basketball dropped from a height of 2.04 m (roughly the height of a professional basketball player). i m/s

YOU HAVE TO SOLVE THE QUESTION (with parts a,b.c) ON AN EMPTY PAPER prepared on the Attendance Part. QUESTION: A very small block of mass m= 0.3 kg is released from rest at point A at a height h= 2.3 m above the ground. It slides down the track as shown in the figure. It reaches point B with speed V= 3.8 m/s. Frorm point B it slides on a horizontal surface a distance d= 1.2 m to point C which is at the bottom of a vertical circular loop of radius R= 16 cm. The circular section of the track (C to D to E) is frictionless but for the remaining section (A to B to C) there is friction. 3. a) Calculate the AE,, (change in thermal energy) for the system between points A and B. b) The coefficient of kinetic friction between the block and the horizontal surface (between B and C) is Hk Calculate u, so that the force on the block by the track at point D is equal to 2mg. c) Find the minimum speed V, with which the block must pass through point C, if it is just not to fall off at the top (point E)…

Part A Compute the kinetic energy, in joules, of an automobile of mass 1650 kg traveling at a speed of 56.0 km/h. Submit Correct Part B Previous Answers By what factor does the kinetic energy change if the speed is doubled? Submit | ΑΣΦ Request Answer BMW ?

A penguin slides down an icy incline on his stomach, as shown in the diagram below. The coefficient of kinetic friction between the incline and the penguin's stomach is 0.15. The angle of the incline is 0 = 25 degrees. The total distance down the incline is 25 meters. The penguin gets a running start so his speed is 2.5 m/s when he begins to slide down the incline. What is the penguin's speed when he reaches the bottom of the incline? Hint: use Newton's 2nd law to calculate the acceleration of the penguin on the incline, then use kinematic equations to calculate the speed of the penguin when he reaches the bottom. 2.5 m/s 25 m 25°

As shown in the figure below, a 2.25 kg block is released from rest on a ramp of height h When the block is released, it slides without friction to the bottom of the ramp, and then continues across a surface that is frictionless except for a rough patch of width 15.0 cm that has a coefficient of kinetic friction - 0.750. Find h (in m) such that the block's speed after crossing the rough patch is 3.10 m/s. Additional Materials muh puch mining 15.0 cm Reading

Solve it correctly please. I will rate accordingly.

After being hit, a 950 g rock with an initial speed of 455 cm/s slides along a horizontal road against a friction force of 1.91 N. a) How long will it take before it stops? b) What is the coefficient of kinetic friction between the surfaces? c) How much kinetic energy did the rock possess after being hit?

You exert a quick push on a 20-g ice cube horizontally along the top of a smooth incline so that it starts moving at a speed of 0.80 m/s, as shown in the figure. After you stop pushing it, the cube slides down the incline as shown in the figure. Calculate the speed of the ice cube when it reaches the bottom of the incline.