is it correct?? if it is correct,please tell me why r=0,z=H??Thanks very much!!!!! The sketch below shows a cylindrical tank that is filled with a liquid of density p. The lid of the tankhas a hole and atmospheric pressure is acting on the surface of the liquid. The tank rotates with aconstant angular velocity w, such that the liquid surface is at a radius r, directly on the undersideof the lid, as shown.HPaPa3PDoFigure source see [4]a) Determine the pressure distribution p in the fluid as a function of r and z.b) Find a formula for the force that acts on the lid due to the pressure of the liquid.c) What is the distance Do of the lowest level of the fluid surface to the bottom of thetank, based on the values provided.Gravitational acceleration: gH71Height:Radius:Angular velocity:9.81 m/s²0.5 m0.3 m3.0 T/S a) dp- of dr + 3 dz=Randbedingungen:b)OP - PutrJPor3² = - pgP = 1Pw²r² - pg = + C 2Y₂ 0₁ Z³ H=C = Pa + PgHP(r. z) = P₂ + 1 Pw²r² + pg (H = =)()auf Deckel : 2 - HP(r. H) = P₂ + 1 Pw²r²→ P: Pa[3R(r·n₁, 2+H) = P₂ + {Pw²ri²+ P9 (Do-H)Spw²ri² = -P9 (D₂-H)Do = H-wa= 0,4587m

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Mechanical Engineering

is it correct?? if it is correct,please tell me why r=0,z=H??

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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is it correct?? if it is correct,please tell me why r=0,z=H??

Thanks very much!!!!!

The sketch below shows a cylindrical tank that is filled with a liquid of density p. The lid of the tank
has a hole and atmospheric pressure is acting on the surface of the liquid. The tank rotates with a
constant angular velocity w, such that the liquid surface is at a radius r, directly on the underside
of the lid, as shown.
H
Pa
Pa
3
P
Do
Figure source see [4]
a) Determine the pressure distribution p in the fluid as a function of r and z.
b) Find a formula for the force that acts on the lid due to the pressure of the liquid.
c) What is the distance Do of the lowest level of the fluid surface to the bottom of the
tank, based on the values provided.
Gravitational acceleration: g
H
71
Height:
Radius:
Angular velocity:
9.81 m/s²
0.5 m
0.3 m
3.0 T/S

a) dp- of dr + 3 dz
=
Randbedingungen:
b)
OP - Putr
JP
or
3² = - pg
P = 1Pw²r² - pg = + C 2
Y₂ 0₁ Z³ H
=
C = Pa + PgH
P(r. z) = P₂ + 1 Pw²r² + pg (H = =)
()
auf Deckel : 2 - H
P(r. H) = P₂ + 1 Pw²r²
→ P: Pa
[3
R(r·n₁, 2+H) = P₂ + {Pw²ri²+ P9 (Do-H)
Spw²ri² = -P9 (D₂-H)
Do = H-wa
= 0,4587m

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