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Investigators performed a randomized experiment in which 414 juvenile delinquents were randomly assigned to either multisystemic therapy (MST) or just probation (control group). Of the 218 assigned to therapy, 92 had criminal convictions within 12 months. Of the 196 in the control group, 75 had criminal convictions within 12 months. Determine whether the therapy caused significantly fewer arrests at a 0.10 significance level. Start by comparing the sample percentages. Find and compare the sample percentages that were arrested for these two groups. The percentage of arrests for people who received MST was (Type an integer or decimal rounded to two decimal places as needed.) The percentage of arrests for people who received probation was ☐ %. (Type an integer or decimal rounded to two decimal places as needed.). The arrest rate was greater for people in the group. Let p represent the population proportion for people who are arrested after having received the treatment and let p2 represent the population proportion of people who are arrested after having not received the treatment. Write the hypotheses for the test. Ho Ha Find the test statistic for this test. z= (Round to two decimal places as needed.) Find the test statistic for this test. Z= (Round to two decimal places as needed.) Find the p-value for this test. p-value = (Round to three decimal places as needed.) What is the conclusion for this test? Use a significance level of 0.10. the null hypothesis. The arrest rate for the people who received MST significantly lower than the arrest rate for the control group.

Investigators performed a randomized experiment in which 414 juvenile delinquents were randomly assigned to either multisystemic therapy (MST) or just probation (control group). Of the 218 assigned to therapy, 92 had criminal convictions within 12 months. Of the 196 in the control group, 75 had criminal convictions within 12 months. Determine whether the therapy caused significantly fewer arrests at a 0.10 significance level. Start by comparing the sample percentages. Find and compare the sample percentages that were arrested for these two groups. The percentage of arrests for people who received MST was (Type an integer or decimal rounded to two decimal places as needed.) The percentage of arrests for people who received probation was ☐ %. (Type an integer or decimal rounded to two decimal places as needed.). The arrest rate was greater for people in the group. Let p represent the population proportion for people who are arrested after having received the treatment and let p2 represent the population proportion of people who are arrested after having not received the treatment. Write the hypotheses for the test. Ho Ha Find the test statistic for this test. z= (Round to two decimal places as needed.) Find the test statistic for this test. Z= (Round to two decimal places as needed.) Find the p-value for this test. p-value = (Round to three decimal places as needed.) What is the conclusion for this test? Use a significance level of 0.10. the null hypothesis. The arrest rate for the people who received MST significantly lower than the arrest rate for the control group.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Investigators performed a randomized experiment in which 414 juvenile delinquents were randomly assigned to either multisystemic therapy (MST) or just probation (control group). Of the 218 assigned to therapy, 92 had criminal convictions within 12 months. Of the 196 in the control group, 75 had criminal convictions within 12 months. Determine whether the therapy caused significantly fewer arrests at a 0.10 significance level. Start by comparing the sample percentages. Find and compare the sample percentages that were arrested for these two groups. The percentage of arrests for people who received MST was (Type an integer or decimal rounded to two decimal places as needed.) The percentage of arrests for people who received probation was ☐ %. (Type an integer or decimal rounded to two decimal places as needed.). The arrest rate was greater for people in the group. Let p represent the population proportion for people who are arrested after having received the treatment and let p2 represent the population proportion of people who are arrested after having not received the treatment. Write the hypotheses for the test. Ho Ha Find the test statistic for this test. z= (Round to two decimal places as needed.)
Transcribed Image Text:Investigators performed a randomized experiment in which 414 juvenile delinquents were randomly assigned to either multisystemic therapy (MST) or just probation (control group). Of the 218 assigned to therapy, 92 had criminal convictions within 12 months. Of the 196 in the control group, 75 had criminal convictions within 12 months. Determine whether the therapy caused significantly fewer arrests at a 0.10 significance level. Start by comparing the sample percentages. Find and compare the sample percentages that were arrested for these two groups. The percentage of arrests for people who received MST was (Type an integer or decimal rounded to two decimal places as needed.) The percentage of arrests for people who received probation was ☐ %. (Type an integer or decimal rounded to two decimal places as needed.). The arrest rate was greater for people in the group. Let p represent the population proportion for people who are arrested after having received the treatment and let p2 represent the population proportion of people who are arrested after having not received the treatment. Write the hypotheses for the test. Ho Ha Find the test statistic for this test. z= (Round to two decimal places as needed.)
Find the test statistic for this test. Z= (Round to two decimal places as needed.) Find the p-value for this test. p-value = (Round to three decimal places as needed.) What is the conclusion for this test? Use a significance level of 0.10. the null hypothesis. The arrest rate for the people who received MST significantly lower than the arrest rate for the control group.
Transcribed Image Text:Find the test statistic for this test. Z= (Round to two decimal places as needed.) Find the p-value for this test. p-value = (Round to three decimal places as needed.) What is the conclusion for this test? Use a significance level of 0.10. the null hypothesis. The arrest rate for the people who received MST significantly lower than the arrest rate for the control group.
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