Interested in exploring the genetic pathways that lead to neurological issues, you want to see if recessive mutations which generate too many neurons (tm) in flies - which many causes autistic like symptoms are in the same gene as mutations that generate too few neurons (tf) - intellectual diabilities. You cross a true-breeding homozygous tm/tm fly to a homozygous too few neuron fly tf/tf. What phenotype in the progeny would tell these mutations are in different genes?
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Interested in exploring the genetic pathways that lead to neurological issues, you want to see if recessive mutations which generate too many neurons (tm) in flies - which many causes autistic like symptoms are in the same gene as mutations that generate too few neurons (tf) - intellectual diabilities. You cross a true-breeding homozygous tm/tm fly to a homozygous too few neuron fly tf/tf. What
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- You are interested in studying position effect variegation in Drosophila using the chromosome depicted below: Deactivation of the w+ gene gives a white eye phenotype and deactivation of the rst+ gene gives a rough eye phenotype; the normal phenotypes are red and smooth. Because the rst+ and w+ genes have now been placed close to a heterochromatic domain, some sections (or sectors) of the eye display mutant phenotypes due to gene deactivation while others display the normal, wild type phenotype. Which phenotype would you not expect to see rst w Inverted X chromosome white smooth eye sectors white rough eye sectors red smooth eye sectors red rough eye sectorsFlies homozygous for recessive null mutations in thesevenless (sev) or bride-of-sevenless (boss) genes have the same mutant phenotype: Every ommatidium(facet) in their eyes lacks photoreceptor cell 7 (R7).The R7 cells enable flies to detect UV light.a. Given that flies normally move toward light, suggest a screening method that would enable you toidentify mutations in additional genes required forR7 determination.b. Would you be able to recover mutations in everygene required for R7 development with yourmethod? Explain.c. How could you tell whether any of the new mutationsyou found in your screen are alleles of sev or boss?d. Suppose you found one recessive mutant allele ofa gene not previously known to be involved in eyedevelopment. How could you use this allele in anew mutagenesis screen to find additional allelesof this gene? Why might you want additional mutant alleles to study the process?Star eye A peculiar eye condition known as "star” is manifested as a dominant gene in Drosophila. Its recessive allele R* produces the normal eye of wild type. The expression of R can be suppressed by the dominant allele of another locus, Ru-R. Ru-R*, as the recessive allele of the said locus, has no inhibitory effect on R*. When a normal-eyed male of genotype Ru-R Ru-R RR is crossed to a homozygous wild-type female of genotype Ru-R* Ru-R* R*R*, what phenotypic ratio is expected in the F2?
- Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior history of the disease. Consider the following pedigree (the darkly colored symbols represent affected individuals): a. Circle the individual(s) in which the mutation most likely occurred. b. Is the person who is the source of the mutation affected by retinoblastoma? Justify your answer. c. Assuming that the mutant allele is fully penetrant, what is the chance that an affected individual will have an affected child?A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes? A recessive mutation pd causes purple eyes in Drosophila, in contrast to the wildtype red eyes. A dominant suppressor called Su can restore the color of pd/pd fly eyes to red. If you cross a pd/+ ; Su/+ fly to a pd/pd ; +/+ fly, what proportion of the offspring will have purple eyes? a. 1/8 b. 1/16 c.1/2 d. 3/16 e. 1/3 f. 3/4 g. 15/16 h. 2/3 i. 1/4A woman diagnosed with early-onset Alzheimer's due to a mutation of the APP genehas children with a man that has no family history of familial Alzheimer's. Give the probability of each possible genotype with corresponding phenotype. (The woman has two possible allele combinations. You must show both possibilities)
- Please explain how you do this question step by step I am very confused! thank you:) You have three independent mutant alleles in the Drosophila gene no-antenna: nan1, nan2 and nan3. You determine the phenotype of Drosophila that are heterozygous for the three alleles (heterozygous for a wild-type allele and a mutant allele), and that are homozygous for the three mutant alleles. The antenna is composed of three segments that are followed at the distal end by a feathery arista (that is the antenna is composed of three segments and an arista). Allele nan1 nan2 nan3 heterozygous Wild-type No arista Wild-type homozygous No arista No antenna No antenna nan1 is a __x__ allele, nan2 is a __y__ allele, and nan3 is a __z__ allele. X Y Z A Dominant negative Null Hypomorphic B Null Dominant negative Hypomorphic C Null Hypomorphic Dominant negative D Hypomorphic Dominant negative Null E Dominant negative Hypomorphic Null Referencing the table above, select the…Concordance studies of twins for a neurodegenerative disorder show MZ= 46% and DZ= 15%. Further studies have shown a possible link to a gene on chromosome 9, however, there are some individuals in the study who have the allele but do not develop the disorder (group 1), and there are other individuals who do not have the allele yet develop the disorder (group 2). Amita's older sister and maternal uncle have this disorder. Currently, Amita & her 2 younger brothers do not show symptoms. Amita's paternal grandfather was rumored to have this disorder. 1. Draw the pedigree for Amita's family and determine the mode of inheritance if any. 2. Explain how the 2 groups in the study could be possible? 3. What would you tell Amita about the heritability of this disorder?APOE gene has been found to be a major contributor to sporadic Alzheimer's disease (AD), by acting as an age-of-onset modifier for the common relatively late-onset forms of the disease. Among four alleles causing early onset of AD, the epsilon4 allele (APOE4) disrupts this function. If you generate transgenic monkeys in which the normal allele of APOE gene is knocked out, what phenotype will you expect for those knockout monkeys? A. The APE mRNA expression will be completely suppressed. B. They slow down the development of AD. C. They develop AD early. D. They don't show any AD symptom.
- Topic: Gene Locus Height in gryphons is determined by a single locus. You cross a two 9' tall gryphons and get 1/4 10'; 1/2 9' and 1/4 8' tall gryphons. If you across two 7' tall gryphons you get 1/4 8', 1/2 7'; 1/4 6' tall gryphons. pls kindly help to explanation: why In gryphons, alleles of the height lous are semidominant and form an allelic series. A.In wheat, aleurone cells form a thin layer of the seed coat that is critical to early gene expression in plant development. The color of this layer of cells is controlled by two alleles of a gene [colored aleurone (R) is dominant to colorless (r)]. A second gene is known to control the color of leaf tips [green leaf tip (G) is dominant to yellow (g)]. Two plants, each heterozygous for both characteristics, are test crossed to homozygous recessives, and their progeny are combined to produce the following totals: colored green 102 colored yellow 98 colorless green 103 colorless yellow 97 a) Use chi-square analysis to test these data for an independent assortment of the two characteristics (table provided). Please show work, how your expected values are calculated, and explain what your results indicate about the data. b) You decide to be cautious in your analysis, and decide to analyze the progeny from each of the crosses individually (instead of adding them together as shown above).…Suppose a geneticist uses a three-point testcross to map three linked Drosophila recessive mutations called f, z, and n. Gene fis associated with abnormally fast movement, z is associated with a zigzag movement pattern, and n is associated with narrow wings. The geneticist first crosses homozygous narrow flies to homozygous fast, zigzag flies. Next, he testcrosses the F₁ progeny to fast, zigzag, narrow parents and obtains the results reported in the table. Based on the data, select the order of the three genes. fzn zfn nzf fnz znf nfz F₁ Testcross Progeny Phenotype narrow fast, zigzag zigzag fast, narrow fast zigzag, narrow fast, zigzag, narrow wild type Number 627 621 209 229 215 223 6 7