int a = 5, b = 12; double x = 3.4, z = 9.1; What are the values of the following expressions? A) b/ a 2 В) х*а 17.0 C) static_cast (x * z) D) static_cast ( static_cast ( x) * static_cast (z) )
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Addition of Two Numbers
Adding two numbers in programming is essentially the same as adding two numbers in general arithmetic. A significant difference is that in programming, you need to pay attention to the data type of the variable that will hold the sum of two numbers.
C++
C++ is a general-purpose hybrid language, which supports both OOPs and procedural language designed and developed by Bjarne Stroustrup. It began in 1979 as “C with Classes” at Bell Labs and first appeared in the year 1985 as C++. It is the superset of C programming language, because it uses most of the C code syntax. Due to its hybrid functionality, it used to develop embedded systems, operating systems, web browser, GUI and video games.
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- Assume the following variable definitions: int a = 5, b = 12; double x = 3.4, z = 9.1; What are the values of the following expressions? A) b / a B) x * a C) static_cast <int> (x * z) D) static_cast<double> ( static_cast<int> ( x) * static_cast <int> (z) )Assume the following variable definitions: int a = 5, b = 12; double x = 3.4, z = 9.1;What are the values of the following expressions?A) b / aB) x * aC) static_cast<double>(b / a)D) static_cast<double>(b) / aE) b / static_cast<double>(a)F) static_cast<double>(b) / static_cast<double>(a)G) b / static_cast<int>(x)H) static_cast<int>(x) * static_cast<int>(z)I) static_cast<int>(x * z)J) static_cast<double>(static_cast<int>(x) * static_cast<int>(z))C++ code 1 year = 15 months 1 month = 30 days write a function that takes an int parameter that represents the number of days, and converts the number of days to years, months, and days and returns this information in a struct So for example, it will convert 800 days into a struct that represents one year, 11 months, and 20 days
- C++ Functions provide a means to modularize applications Write a function called "Calculate" takes two double arguments returns a double result For example, the following is a function that takes a single "double" argument and returns a "double" result double squareArea(double side){ double lArea; lArea = side * side; return lArea;}Code Example: def get_volume (width, height, length=2): volume width * * height length return volume def main (): 1 3 W = 4 h = 5 V = print (v) = get_volume (1, w, h) if name main () "1 main : 1.) Refer to the Code Example: What value is passed to the height argument by the call to the get_volume() function?C++: Describe how the following call by reference works. Make a comment for each line. void pxc(int& c, int& d) { int k = c; c = d; d = k; } int main() { int a = 15, b = 100; pxc(a, b); }
- #include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05); cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…Functions With Parameters and No Return Values Quiz by CodeChum Admin Create a program that accepts an integer N, and pass it to the function generatePattern. generatePattern() function which has the following description: Return type - void Parameter - integer n This function prints a right triangular pattern of letter 'T' based on the value of n. The top of the triangle starts with 1 and increments by one down on the next line until the integer n. For each row of in printing the right triangle, print "T" for n times. In the main function, call the generatePattern() function. Input 1. One line containing an integer Output Enter·N:·4 T TT TTT TTTT#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…
- #include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…Fill-in-the-Blank When used as parameters, _________ variables allow a function to access the parameter’s original argument.C++ printSmaller is a function that accepts two int parameters and returns no value. It will print the value of the smaller one parameters. The function protoype is as follows: void printSmaller(int num1, int num2); write the statments to read two integers and call this function to display the smaller one.