increasing the temperature of the reaction The equilibrium shifts in the direction of reactants. The equilibrium shifts in the direction of products. The equilibrium does not change. Submit Request Answer Part B decreasing the volume of the reaction container O The equilibrium shifts in the direction of products. The equilibrium shifts in the direction of reactants. The equilibrium does not change. Submit Request Answer Part C adding a catalyst The equilibrium shifts in the direction of products. O The equilibrium shifts in the direction of reactants. O The equilibrium does not change. Submit Request Answer Part D adding more Na(g) The equilibrium shifts in the direction of reactants. The equilibrium shifts in the direction of products. O The equilibrium does not change.

increasing the temperature of the reaction The equilibrium shifts in the direction of reactants. The equilibrium shifts in the direction of products. The equilibrium does not change. Submit Request Answer Part B decreasing the volume of the reaction container O The equilibrium shifts in the direction of products. The equilibrium shifts in the direction of reactants. The equilibrium does not change. Submit Request Answer Part C adding a catalyst The equilibrium shifts in the direction of products. O The equilibrium shifts in the direction of reactants. O The equilibrium does not change. Submit Request Answer Part D adding more Na(g) The equilibrium shifts in the direction of reactants. The equilibrium shifts in the direction of products. O The equilibrium does not change.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Octane (112.224 g/mol) undergoes combustion to form carbon dioxide gas and water vapor: 2 C8H18 (l) + 25 O2 (g) → 16 CO2 (g) + 18 H2O (g) ΔH°rxn = -1.01 x 105 kJ Given that the density of octane is 0.703 g/mL, what volume of octane must undergo combustion to produce 524 kJ of heat?
Energy cannot be created nor destroyed, but it can be transferred between a system and its surroundings. The change in internal energy, AU, is positive if the system absorbs energy, and it is negative if the system releases energy. (Figure 1) The total change in internal energy is the sum of the heat, q, and work, w: AU =q+w. Figure 1 of 1 Surroundings AU pystem u System >0 Surroundings AU system System u <0 AU = q + w
CaSO4.5H2O + heat → ____ CaSO4(s) + ____ H2O
125 g of water are mixed with 10.5 g of KBr. The initial temperature was 24.2 °C and the final temperature was 21.1 °C. What was the enthalpy change of the water? AH = m x c x AT
Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia: N₂(g) + 3H₂(g) 2 NH3(g) In the second step, ammonia and oxygen react to form nitric oxide and water: 4 NH3(g) + 50₂(g) → 4 NO(g) + 6 H₂O(g) ΔΗ = - 92. kJ kJ Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. Round your answer to the nearest kJ. X AH = -905. kJ
Given the following thermochemical equations: 2 OF2 (g) →→→ 02 (g) + 2 F2 (g) 2 CIF (g) + O2 (g) → C120 (g) + OF2 (g) CIF 3 (g) + O2 (g) → Cl20 (g) + 3/2 OF2 (g) AH = -49.4 kJ AH = +205.6 kJ AH = +266.7 kJ Calculate the enthalpy change (in kJ) for this reaction: CIF (g) + F2 (g) → CIF3 (g) Show your complete solution. Express your answer in two decimal places.
When methanol, CH, OH, is burned in the presence of oxygen gas, O₂, a large amount of heat energy is released. For this reason, it is often used as a fuel in high performance racing cars. The combustion of methanol has the balanced, thermochemical equation CH₂OH(g) + O₂(g) → CO₂(g) + 2 H₂O(1) AH = -764 kJ How much methanol, in grams, must be burned to produce 983 kJ of heat? mass: g
Nitric oxide (NO) can be formed from nitrogen, hydrogen and oxygen in two steps. In the first step, nitrogen and hydrogen react to form ammonia: N₂(g) + 3 H₂(g) 2NH,(9) In the second step, ammonia and oxygen react to form nitric oxide and water: 4NH3(g) + 5O₂(g) 4 NO(g) + 6H₂O(g) ΔΗ=-905. kJ Calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. Round your answer to the nearest kJ. kJ ΔΗ= -92. kJ X
The following thermochemical equation is for the reaction of carbon dioxide(g) with hydrogen (g) to form acetylene(g) (C₂H₂) and water(g). 2CO₂(g) + 5H₂(g)→→→→→→ C₂H₂(g) + 4H₂O(g) ΔΗ = 46.5 kJ When 10.9 grams of carbon dioxide (g) react with excess hydrogen (g), kJ of energy are Hint: An amount of energy is expressed as a positive number. The sign of AH in the thermochemical equation indicates whether the energy is absorbed or evolved.
20.0 g of a solid substance X initially at 25.0 °C is heat to its melting point at 65.0 °C. Heat is continuously added until the substance completely melts. Which expression represents the total heat added (q) to X in units of kJ? Variables are defined below: J CX = specific heat of X in C MM (X) = molar mass of X in g mol AH fus = enthalpy of fusion of X in kJ AHvap = enthalpy of vaporization of X in kJ kJ q= (C) (20.0 g) (65.0°C 25.0°C) (100) + (20.0 g) (AHfus) J q= (CX) (20.0 g) (65.0°C - 25.0°C)(₁) 1000 J g q= (CX) (20.0 g) (65.0°C - 25.0°C)+(X)(AHfus) kJ 20.0 g q= = (CX) (20.0 g) (65.0°C - 25.0°C) (1000) + (MMX)) (AHfus) J 20.0 g 9 = (MMX) (AHvap) q= (CX) (20.0 g) (65.0°C 25.0°C) (1000)+( kJ 20.0 g MM (X)) (AHvap) 20.0 g q= (CX) (2) (65.0°C - 25.0°C)(110)+(2)(AHfus) J kJ
Coffee cup calorimetry was used to determine the enthalpy of solution of lithium iodide (LiI): A) First, the coffee cup was calibrated. 50.0 mL of water (s=4.184J/g×0 C) was heated to 95.50C and mixed with 50.0 mL of cool water at 22.30 C. The temperature of the contents of the coffee cup stabilized at 49.40 C. Determine the heat capacity of the coffee cup. B) Next, the enthalpy of solution of lithium iodide (LiI) was determined. 0.0g of solid lithium iodide was added to 100mL of water at 23.20 C in the coffee cup, and the temperature increased to 32.10 C. Calculate the enthalpy of the solution of lithium iodide.
In one box of nails, there are 75 iron nails weighing 0.280 lblb . The density of iron is 7.86 g/cm3g/cm3. The specific heat of iron is 0.452 J/g∘CJ/g∘C. The melting point of iron is 1535 ∘C∘C. A)How much heat, in joules, must be added to the nails in the box to raise their temperature from 16 ∘C∘C to 123 ∘C∘C? B)How much heat, in joules, is required to heat one nail from 31 ∘C∘C to its melting point?