Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Question
1. Which of the following options is a viable way to increase the Vmax of an enzymatic reaction?
Increase the amount of substrate present. |
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Increase the amount of enzyme present. |
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Decrease the temperature of the reaction. |
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Decrease the Km of the enzyme. |
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- 1. Construct a model that demonstrates how enzyme catalyzed reactions harvest energy from simple carbohydrates.arrow_forward1. Compare and contrast the activation free energy and the free energy change for an enzyme-catalyzed reaction.arrow_forward1. The enzyme you are studying uses the substrate pictured at right. An inhibitor box in the freezer contains two tubes labeled Inhibitor #1 and Inhibitor #2, along with the structures of the compounds contained within them and their respective Ki. Which one is more likely to be the non-competitive inhibitor? Inhibitor #1 K₁ = 10 μM m CH₂OH OH -0, $ OH OH Inhibitor #2 K₁ = 50 μM Briefly Justify: OH CH₂OH OH OH OH Substratearrow_forward
- 22. What is a major benefit of calculating catalytic efficiencies? Group of answer choices It determines whether a catalytic reaction is cooperative It allows you to compare different substrate preferences for an enzyme It tells you the rate of an enzyme reaction It allows you to determine the efficiency of the enzyme being studiedarrow_forward1. define in your own words enzyme 2. explain how enzymes act on a substrate 3. explain the term catalyst 4. what is meant by optimal conditions for enzymes and what are the conditions 5. explain what catalase is: what it helps to break down and into what parts.arrow_forward15) The graph at right shows the results of reaction rate vs. substrate concentration for a Michaelis-Menten type enzyme 16) Th a. True b. False* reaction rate substrate concentrationarrow_forward
- 3. Enzyme specificity. To determine the specificity of substrate binding for a particular enzyme/protein, structurally related compounds may be used as potential substrates and Km values may be calculated. However, many compounds structurally related to the substrate may bind to the active site but cannot be converted to product. In these instances, the substrate analogs are used as potential competitive inhibitors of substrate binding. Low K, values indicate high affinity of the enzyme for the inhibitor, whereas high K,values indicate low binding affinity. Consider the enzyme xanthine oxidase, which catalyzes the formation of uric acid from the purine bases hypoxanthine or xanthine in humans. The Km for hypoxanthine is 15.0 μM and for xanthine it is 45.0 μM. A few compounds used as competitive inhibitors of the normal substrate hypoxanthine are listed in the table below with their K; values. Comparing the structures of hypoxanthine with the listed substrate analogs, what can you…arrow_forwardWith a ∆G°´ of -16.7 kJ/mol, the reaction catalyzed by hexokinase is considered to be _____. at equilibrium substrate and product concentration dependent freely reversible metabolically irreversible none of the abovearrow_forward8.Choose the False statement about enzyme binding sites Binding at an allosteric site ca affect binding and catalysis at the Ortho steric site. In addition to ortho steric sites , some enzymes have other sites where catalysis can be conducted. They are called , allosteric sites, from “allo,” the other. In principle, allosteric ligands can have structures that do not resemble those of substrates. Ligand binding at an allosteric site can cause a conformational change of an enzyme. Enzyme can be inhibited by an allosteric ligand that does not complete with substrate.arrow_forward
- Consider the following free energy diagram for an uncatalyzed and enzyme-catalyzed reaction. Select all the statements that are true. Without enzyme With enzyme A+B Time AB Oa. The reaction is now spontaneous due to the addition of enzyme b. The rate of the enzyme catalyzed reaction is faster than the uncatalyzed reaction O C. The reaction is exergonic O d. The change in free energy for the reaction is greater in the catalyzed reaction, compared to the uncatalyzed reaction e. The enzyme stabilizes the transition state for the reaction Released Energy pesarrow_forward14. In competitive inhibition, an inhibitor— binds reversibly at the active site. binds to both free enzyme and the ES complex. binds at several different sites on an enzyme. binds only to the ES complex. binds covalently to the enzyme.arrow_forward
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