included in the confidence interval range, Since the we can conclude that there is the manufacture's claim at a 10% significance level.
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- Independent students show that the average length of education of 70 r/s California adults is 12.7 years with standard deviation 5.33 years, while the figures of 36 r/s Hawaii adults are 14.2 and 3.15 . Construct a 98% confidence interval for the difference between the overall average length of educations of California adults and that of Hawaii adults.An SRS of 27 students at NYU gave an average height of 5.4 feet and a standard deviation of .1 feet. Find a 90% confidence interval for the mean height of students at NYU.17 walleyes from Lake Erie were sampled and found to have a mean weight of 2.4 pounds with astandard deviation of .73 pounds. Find a 95% confidence interval for the weight of walleyes inLake Erie.
- A group of students sampled water from 34 lakes in St. Joseph County. If the mean dissolvedoxygen level was 3.2 with a standard deviation of .57 find a 90% confidence interval for thedissolved oxygen levels in St Joseph County lakes.A small university is trying to monitor its electricity usage. For a random sample of 30 weekend days (Saturdays and Sundays), the student center used an average of 94.26 kilowatt hours (kWh) with standard deviation 43.29. For a random sample of 60 weekdays, (Monday - Friday), the student center used an average of 112.63 kWh with standard deviation 32.07. Construct a 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days. Use two decimal places in your margin of error. -6.80 to 43.54 kWh -4.61 to 41.35 kWh -3.38 to 40.51 kWh 0.12 to 36.62 kWhA random sample of 15adultRainbow trout in a fish hatchery showed the average weight was 3.5pounds and a standard deviation of 0.8 pounds. Constructa 90% confidence interval for the average weight of the trout at the hatchery.
- An SRS of 23 students at TSU gave an average height of 5.6 feet and a standard deviation of .1 feet. Construct a 90% confidence interval for the mean height of students at TSU.Tire pressure (psi) and mileage (mpg) were recorded for a random sample of seven cars of thesame make and model. The extended data table (left) and fit model report (right) are based on aquadratic model Question: Note that highlighted 95% confidence interval for the mean mileage at tire pressure x=31 in the data table. Interpret the highlighted interval (31.77, 35.09) in the context of the tire pressure applicationA study of 22 goats reveals that the average length of a goat’s tail is 6.3 inches. If the standarddeviation is known to be 1.2 inches find a 95% confidence interval for the mean tail length.
- A random sample of 180 adults male wolves from the Canadian Northwest Territories gave an average weight of 98 pounds, with standard deviation 6.5 pounds. Another sample of 85 adult male wolves from Alaska gave an average weight 90 pounds, with standard deviation 7.3 pounds. Construct a 91% confidence interval for the difference between two population means.Dr. Moore wanted to estimate the mean cholesterol level for all adult men living in Hartford. He took a sample of 25 adult men from Hartford and found that the mean cholesterol level for this sample is 186 mg/dL with a standard deviation of 12 mg/dL. Assume that the cho- lesterol levels for all adult men in Hartford are (approximately) normally distributed. Con- struct a 95% confidence interval for the population mean u.The advertised weight of oranges in an ad is 8.5 ounces. Fifty oranges were randomly selected and weighed at a distribution facility. The mean weight for this sample was 8.3 ounces with a standard deviation of 1.5 ounces. Construct and interpret a 95% confidence interval for the true mean weight of oranges at this facility and comment on how this interval related to the claim in the ad.