q1 a One of the customer service department received the following number of calls duringpeak time over 12 time periods:50, 49, 63, 54, 72, 76, 59, 66, 83, 64, 78, 61It is known that the standard deviation of the number of calls during peak time is 16. Estimate themean number of calls over peak time with a 98% confidence level.

Since population sd is known, using Normal distribution to calculate confidence interval.

Answered: One of the customer service department…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.4: Distributions Of Data

Problem 3GP

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 16 days.In what range would you expect to find the middle 98% of most pregnancies? (Use a single sample)Between _ and _ days.If you were to draw samples of size 59 from this population, in what range would you expect to find the middle 98% of most averages for the lengths of pregnancies in the sample?Between _ and _ days.
The Vice President (Academics), International University , wouldlike to know if students who use the software score better on exams. A sample of students whoused the software had the following exam scores: 86, 78, 66, 83, 84, 109, 65, and 102. Studentswho did not use the software had the following exam scores: 91, 71, 75, 87, 79, 78, 87, 90, 76,and 72. Assume the population standard deviations are not the same. At the .10 significancelevel, can we conclude that there is a difference in the mean exam scores for the two groups ofstudents?
One of customer service department received the following number of calls during peak time over 10 time periods: 50, 47, 69, 55, 71, 77, 52, 63, 81, 64 It is known that the standard deviation of the number of calls during peak time is 15. Estimate the mean of number of calls over peak time with 99% confidence level. A researcher claims that some particular bacteria with an average life span of 12 hours will live to be about 20 hours when 25% of environment is more suitable for a longer lifespan. Is there any reason to believe that the mean is less than 21 if 31 bacteria that are placed on this suitable environment have an average life of 18 hours with a standard deviation of 4.8 hours? Use a 0.10 level of significance.

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