In this figure (page 259) explain why the EMG and torque curves look the way that they do. **Be detailed. the explElbow Torque (Nm)88Biceps Brachi EMG (V)0940206TorqueConcentric0.5 1.01IAngleEccentric2.0253.02Elbow Torque (Nm)Biceps Brachi EMG (V)2222&Torque0.5Les HautConcentric1.01.5IIAngleEccentric2.02.53.01501208Elbow Angle (deg)8303.5

Given: To find: Explain the graph

Answered: In this figure (page 259) explain why…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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TI=30NM, T2=155NM, T3=85NM and dBC=22mm. 12 010 T3 T2 T1 3-1892615112 D 010 b180106003- 1892615112 \dcp 1826151126 b180106003-18926 dBC B. `dAB b180100003-18926151126 In the figure above, torques TI, T2 and T3 are applied, respectively, to discs A, B and C on the shaft, which is fixed at point D. 3-1892815112s b180106003-18926 The diameters of the shaft segments are indicated in the figure and their values are given below (if they are required). Length of each segment on the shaft has the same value and is equal to L(AB)=L(BC)=L(CD)=400 mm. b180106003- 18926151126 Shear modulus of the material is 80 GPa. o-18926151126 b180108003-18926 Calculate the maximum shear stress g003-18926151126 003-18926 b18 on shaft segment BC. 010600s28151128 B A 46 MPa 60 MPа b180106003- 18926 b180106003- 1892615112 b180106003- 18928151126 38 MPa b180100003-1892615112 57 MPa b180106003- 18926151126 E b180108003-18928 31 MPа b180106003- 18926151126 b180106003- 18926151128 b180106003- 18928151126…
Assuming there is no axial thrust, find the reactions @ A & C. Y Note: Force actlig on gear B is parallel to z-axis. Force acting on year D is parallel to y-ax's. 50 70015 3010 25 in 86916 201 100
1| * tiRE IŠ SHAFT IS RoT&TED S RETARDED, FF tHE NATURAL FREQUENCY IS O671 HZ. CALCULATE tHE STIFFNESS OF THE XXLE SHAFT, kp in N/m. I0kg XND CONNECTED to AN AXLE 9. 1,070 Ci 199.0010 d. 10 3, 1416.10
Q4:- The turning moment diagram of one revolution of multi cylinder engine above and below the line of mean resisting torque are given by (-0.32, 4.06, -2.71, 3.29,-3.24, 2.4, -3.74, 2.71, -2.45) cm?. The fluctuation of speed is limited to 1 1.5 percent of mean speed which is 250 rpm. The hoop stress in rim material is limited to 549.2 N/cm2. Neglecting of boss and arm effects , determine the suitable diameter and cross section of flywheel rim if the weight density of rim material is 0.0706 N/cm. Assume that the width of rim equals four times its thickness. Hint: the vertical and horizontal scales are 1 cm=588600 N.cm and 1 cm= 24° respectively.
In a gearbox, a spur gear is mounted on a shaft at equal distances from twosupporting bearings. The shaft and mounted gear turn together at a speed of3600RPM. The gearbox is designed to transmit a maximum power of 3kW. Thegear contact angle is φ = 20°. The pitch diameter of the gear is dp = 30 in. a) Findthe radial force on each of the two bearings supporting the shaft.The ratio of the two bearings’ length and diameter is L/D = 0.5. The bearings aremade of acetal resin material with the following limits:Surface velocity limit, V, is 5m/s.Average surface-pressure limit, P, is 7 MPa.PV limit is 3000 psi-ft/min.b) Find the diameter of the shaft in order not to exceed the stated limits.
Q4:- The turning moment diagram of one revolution of multi cylinder engine above and below the line of mean resisting torque are given by (-0.32, 4.06, -2.71, 3.29,-3.24, 2.4, -3.74, 2.71, -2.45) cm?. The fluctuation of speed is limited to t 1.5 percent of mean speed which is 250 rpm. The hoop stress in rim material is limited to 549.2 N/cm?. Neglecting of boss and arm effects , determine the suitable diameter and cross section of flywheel rim if the weight density of rim material is 0.0706 N/cm. Assume that the width of rim equals four times its thickness. Hint: the vertical and horizontal scales are 1 cm=588600 N.cm and 1 cm= 24° respectively.
Falcon company Nizwa is conducting a campus interview to you. You are asked to design the propeller shaft with the following specification. (i) power tranmission = 290 kW(ii) speed = 60 rpm,(iii) Maximum shear stress = 65 MPa(iv) diameter ratio = 1.5(v) The maximum value of the twisting moment is 40% greater than its mean. The mean torque is (Unit is in Nm)=__________ (ii) The maximum torque is (Unit is in Nm)=__________ (iii) The outer diameter of the shaft (unit in mm)=_______________ (iv) The inner diameter of the shaft (unit in mm)=_______________
Q4:- The turning moment diagram of one revolution of multi cylinder engine above and below the line of mean resisting torque are given by (-0.32, 4.06, -2.71, 3.29,-3.24, 2.4, -3.74, 2.71, -2.45) cm. The fluctuation of speed is limited to t 1.5 percent of mean speed which is 250 rpm. The hoop stress in rim material is limited to 549.2 N/cm?. Neglecting of boss and arm effects , determine the suitable diameter and cross section of flywheel rim if the weight density of rim material is 0.0706 N/cm³. Assume that the width of rim equals four times its thickness. Hint: the vertical and horizontal scales are 1 cm-588600 N.cm and 1 cm3 24° respectively.
A static shaft is subjected to torques at A, B, and C. It has a diameter of 58 mm and is made from 2014-T6 aluminum. If the maximum allowable magnitude of the angle of twist of C relative to A is 0.04 rad, what is the maximum value for the torque T? A aT T cc i❀O 2021 Cathy Zupke parameter value 1.4 1.6 0.6 L₁ L2 α B units m m [-] (1-a )T The maximum value for T is 1.56 X kN.m.
The turning moment diagram for a multi cylinder engine has been drawn toa scale of 1 mm = 4500 N -m vertically and 1 mm = 2. 4 ͦ horizontally. Theintercepted areas between output torque curve and mean resistance lineabove and below the mean taken in order from one end are 342, 23, 245,303, 115, 232, 227, 164 ??2, when the engine is running at 150 rpm. Ifthe mass of the flywheel is 1000 kg and the total fluctuation of speed doesnot exceed 3% of the mean speed, find the minimum value of the radius ofgyration.
2. For the linkage shown in Fig. 2, determine VB and 004. auquo od to enoblog lugna adi snimateb 11 ge 200 to styd (SB048-2 in. 02 mmm. min 501 45° 3 Figure 2. 4 04 0₂04 = 4 in. 0₂A - 2.828 in 104 AB= in. 2 14.14 rad/s ccw
The driving shaft of a Hool joint rotates at a uniform sp. of 400 rpm. If the maxim variation in speed of the dri shaft is + 5% of the mean speed, determ the greatest permissible angle between axes of the shafts. What are the maxim and the minimum speeds of the driven sho

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