In this example, we will analyze the motion of an electron that is released in an electric field. The terminals of a 100 V battery are connected to two large, parallel, horizontal plates 1.0 cm apart. The resulting charges on the plates produce an electric field Ē in the region between the plates that is very nearly uniform and has magnitude E = 3.0×104 N/C. Suppose the lower plate has positive charge, so that the electric field is vertically upward, as shown in (Figure 1). (The thin pink arrows represent the electric field.) If an electron is released from rest at the upper plate, what is its speed just before it reaches the lower plate? How much time is required for it to reach the lower plate? The mass of an electron is me = 9.11 x 10-31 kg The thin arrows represent the uniform electric field. 1.0 cm 100 V In this example, suppose a proton (mp = 1.67 × 10-27 kg) is released from rest at the positive plate. What is its speed just before it reaches the negative plate? Express your answer with the appropriate units. HẢ ? |v| = Value Units

An electron is moving east with a speed 6.00 x 105 m/s in a uniform electric field. Magnitude of the electric field is 2.00 N/C directed to the west. What is the speed of the electron when it travels 0.50 m in the east direction? Please write your answer in km/s.

An electron enters the region of a uniform electric field as shown e. (0, 0) (x, y) + + + + with vi = 6 x 10° m/s and E=215 N/C. The horizontal length of the plates is l = 0.100 m. What is the magnitude of electron's acceleration while it is in the electric field? Assuming the electron enters the field at time t 0, find the time at which it leaves the field search 近

A closed surface is constructed in the space between two large parallel metal plates, where there is a constant electric field E. The magnitude of the field is El=1170 N/C. The numbers (1), (2), and (3) in the simulation label small increments of area of 1.5 cm² on the surface. The direction of each increment is defined to be the direction of a vector out of the surface and perpendicular to the increment's surface area. With that definition assume the direction of the first increment AA, is 65° from the direction of E, that the second increment AÃ, is oriented 90° from the direction of E, and that the third increment AA is oriented 135 from the direction of E. Find the flux through each of the three increments of area. For area AA, Nm²/C For area A For area A Pemb 9- Nm²/C Nm²/C