Answered: In the titration of 25.0 mL of 0.150 M…

In the titration of 25.0 mL of 0.150 M sodium lactate, CH3CHCOONa (Ka (lactic acid, CH3CHCOOH)= 1.4 x 10-4) with 0.250 M HCI, the pH after adding 15.0 mL of HCl is: O 7.00 O 12.46 O2.44 O 6.58 O 1.96

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.74PAE

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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uestion 5
In the titration of 25.0 mL of 0.150 M sodium lactate, CH3CHCOONa (Ka (lactic acid, CH3CHCOOH)= 1.4 x 10-4) with 0.250 M HCl, the pH after adding 15.0 mL of HCl is:
O 7.00
O 12.46
O2.44
O 6.58
O 1.96

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