Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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In the same population of locusts, the mean wing length is 47 mm, the selection gradient on wing length is β = 0.12/mm, the
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- Eye color in a species of fruitfly is determined by a single locus with two alleles: E and e. EE individuals have red eyes, Ee have pink eyes, and ee individuals have brown eyes. In a lab population that is in Hardy–Weinberg equilibrium, we count 27 flies with brown eyes out of 164. How many flies can you expect to have red eyes? Round your answer to the closest integer value.arrow_forwardIn a population of the annual, self-compatible, Ipomoea purpurea, allele frequencies at a neutral genetic marker with two alleles are p=0.7; q=0.3 in generation 1. Assume this population in generation 1 was initially in Hardy Weinburg equilibrium. In this year, pollinators are absent and all plants self-fertilize, thus producing only self-fertilized seeds. Is the population in this second generation (i.e the offspring) still in Hardy Weinburg equilibrium? Show your work or explain your answer.arrow_forwardA population of 40 asters segregating at two loci with two alleles each (A/T and G/C) has 8 individuals with the AAGGgenotype. The allele frequencies of A and G are 0.5 and 0.5 in the population. What is the coefficient of gametic disequilibrium, D? What is the value of Lewontin’s D’? (that is “D prime”)arrow_forward
- Below is a diagram showing decreased fitness before and after a hypothetical bottleneck in which all of the inbreeding depression is due to increased homozygosity for deleterious recessive alleles. The open circles show the average fitness of hypothetical 'mutant-free' individuals that have no deleterious alleles. The shaded circles show the average fitness of individuals produced by random mating. The dark circles show the average fitness of individuals with an Fof 0.25 (equivalent to full-sib matings). In the diagram on the right, imagine that 'before' refers to before genetic rescue has been instituted (that is, before managed gene flow into a small and isolated population). The circles are defined the same as above. Draw what the circles (unfilled, grey filling, and dark filling) would look like in the 'after' portion of the diagram, that is, after a single pulse of gene flow from a small number (~5) of translocated individuals, if fixed genetic load decreases in this population.…arrow_forwardLast summer you were walking in the woods when you stumbled upon a group of four tiny baby squirrels. You noticed that they all had different tail lengths. Curious, you decided to measure the tail lengths of the four squirrels. Their tail lengths were found to be: 30 mm, 38 mm, 32 mm, and 28 mm. The heritability for tails in squirrels is 0.33. (This is a fraction, not percent.) What is the variance due to the difference in environment (VE)? Round to two decimals and do not include units.arrow_forwardA population of sea cucumbers from the maldives has the following allele frequencies for the tentacle colour gene; A= 0.7 and a=0.3. Using Hardy Weinberg equations and these allele frequencies, what are the expected genotype frequencies in the population?arrow_forward
- The absolute fitnesses of the three genotypes in a two-allele system are given as follows: Genotype Absolute Fitness AA 0.08654 Aa 0.32143 aa 0.01662 What is the strength of selection against (i.e., the selection coefficient of) the Aa genotype? (Numerical answer; please do you all your work with at least 5 digits of precision)arrow_forwardCerebellar abiotrophy (CA) is a recessive, genetic neurological disease found in the Arabian horse breed. If the incidence of this disease is about 1 in 400 Arabian horses, estimate the frequency of carriers in a population in Hardy-Weinberg equilibrium. Value of q²: 0.0025 Value of q: 0.05 Value of p: 0.95 Carrier Frequency: 0.095 How many horses would you expect to be carriers for cerebellar abiotrophy if the population consists of 582 Arabian horses? (Round to the nearest whole number and enter 2 digits.)arrow_forwardPretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…arrow_forward
- In a population of cats, 12 cm^2 is the additive genetic variance for lenght of tail and 16 cm^2 is the total phenotypic variance. Based on these answer the followinng ques: Find the narrow sense heritability for this length of tail in the population of cats. What would be the covariance of two cats who are related to one another as being first cousins?arrow_forwardConsider an autosomal locus with alleles A and a. If the the allele frequencies are as follows Freq(A) = 0.4, Freq(a) = 0.6. , then what is the predicted frequency of heterozygous Aa individuals, assuming the population is in Hardy-Weinberg equilibrium? Freq(Aa) = ? Enter a number between 0 and 1, inclusive, for example 0.33arrow_forward
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