In the reaction shown below, the standard Gibbs energy of formation and standard enthalpy of formation of the reactants and products at 25°C are given. Calculate the standard Gibbs energy of reaction, the standard enthalpy (kJ/mol) of reaction, and the equilibrium constant at 298K. A 4G (KJmol-1) -160.55 AH (KJmol-1) -178.12 (a) 4.G°(298K)= (b)4 H°(298K)= (c)K(298K)= + B -167.17 -141.53 = C + D -31.22 -79.55 -344.36 -393.51 (kJ/mol, round to 2 decimals, such as -25.67) (kJ/mol, round to 2 decimals, such as -25.67) (use E notation with 1 decimal such as 2.5E3 for 2515)
In the reaction shown below, the standard Gibbs energy of formation and standard enthalpy of formation of the reactants and products at 25°C are given. Calculate the standard Gibbs energy of reaction, the standard enthalpy (kJ/mol) of reaction, and the equilibrium constant at 298K. A 4G (KJmol-1) -160.55 AH (KJmol-1) -178.12 (a) 4.G°(298K)= (b)4 H°(298K)= (c)K(298K)= + B -167.17 -141.53 = C + D -31.22 -79.55 -344.36 -393.51 (kJ/mol, round to 2 decimals, such as -25.67) (kJ/mol, round to 2 decimals, such as -25.67) (use E notation with 1 decimal such as 2.5E3 for 2515)
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 83QRT: Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate,...
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plz answer 5 and i use 6 for a follow up question
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