College Physics
College Physics
10th Edition
ISBN: 9781285737027
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Educational Content: Analysis of an RC Series Circuit**

**Circuit Description:**
In the RC (series) circuit, the resistance \( R \) is 1.2 MΩ and the capacitance \( C \) is 5.00 μF. The circuit is connected to a 30-volt power source. A switch \( S \) is included for controlling the circuit operation.

**Circuit Diagram:**
The diagram shows a resistor \( R \) and a capacitor \( C \) connected in series with each other, and they are connected to an electromotive force (EMF) source labeled \( \mathcal{E} \), which is 30 volts. The switch \( S \) is placed in the circuit to close or open the connection to the power source. 

**Question:**
What is the current in the circuit when the capacitor reaches 25 volts?

**Options:**
- a. 2.12 μA  
- b. 4.17 μA  
- c. 9.3 μA  
- d. 12.4 μA  

To solve this problem, use the formula for current in an RC circuit:
\[ I = \frac{V_{\text{source}} - V_{\text{capacitor}}}{R} \]
where:
- \( V_{\text{source}} \) is 30 volts.
- \( V_{\text{capacitor}} \) is 25 volts.
- \( R \) is 1.2 MΩ. 

Using these values, you can calculate the current in the circuit when the capacitor has charged to 25 volts.
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Transcribed Image Text:**Educational Content: Analysis of an RC Series Circuit** **Circuit Description:** In the RC (series) circuit, the resistance \( R \) is 1.2 MΩ and the capacitance \( C \) is 5.00 μF. The circuit is connected to a 30-volt power source. A switch \( S \) is included for controlling the circuit operation. **Circuit Diagram:** The diagram shows a resistor \( R \) and a capacitor \( C \) connected in series with each other, and they are connected to an electromotive force (EMF) source labeled \( \mathcal{E} \), which is 30 volts. The switch \( S \) is placed in the circuit to close or open the connection to the power source. **Question:** What is the current in the circuit when the capacitor reaches 25 volts? **Options:** - a. 2.12 μA - b. 4.17 μA - c. 9.3 μA - d. 12.4 μA To solve this problem, use the formula for current in an RC circuit: \[ I = \frac{V_{\text{source}} - V_{\text{capacitor}}}{R} \] where: - \( V_{\text{source}} \) is 30 volts. - \( V_{\text{capacitor}} \) is 25 volts. - \( R \) is 1.2 MΩ. Using these values, you can calculate the current in the circuit when the capacitor has charged to 25 volts.
Expert Solution
Check Mark
Step 1

Given:

Resistance R=1.2 MΩ

Capacitor C=5.0 μF

E.M.F. of battery ε=30 V.

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