In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the CH is in the direction of A=7+7+R and an adjacent C-H bond is at the direction B=1-7-R. results to an angular bond of approximately 1090 for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1i + 0.98j + 0.83k B = 0.98i + -1.01j + -0.99k What is the angle (in degrees) between the bonds based on this new data?

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter24: Electric Fields
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In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of

In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the
CH is in the direction of
A= î++R
and an adjacent C-H bond is at the direction
B=1-1-R.
results to an angular bond of approximately 109° for a static frozen molecule.
However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary
slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be
A = 1i + 0.98j + 0.83k
B = 0.98i + -1.01j + -0.99k
What is the angle (in degrees) between the bonds based on this new data?
Note: Only 1% of error is permitted for the correct answer.
Transcribed Image Text:In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the CH is in the direction of A= î++R and an adjacent C-H bond is at the direction B=1-1-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1i + 0.98j + 0.83k B = 0.98i + -1.01j + -0.99k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
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