Consider the circuit shown in the figure, with C, - 5.42 µF and C, - 7.14 pF. 6.00 uF HP 2.00 uF 90.0 V (a) Find the equivalent capacitance (in uF) of the system. HF (b) Find the charge (in µC) on each capacitor. . 5.42 pF capacitor 4.185 Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q - CAV. Use this information to help you determine the charge on each capacitor. µC 37.7 6.00 uF capacitor Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q - CAV. Use this information to help you determine the charge on each capacitor. µC 23.5 7.14 pF capacitor Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q = CAV. Use this information to help you determine the charge on each capacitor. µC 2.00 pF 14.2 сараcitor Note that the same potential difference, equal to the potential difference of the battery, exists across both the upper and lower branches. Recall that each of the capacitors in series combination holds the same charge as that on the equivalent capacitor, and that Q = CAV. Use this information to help you determine the charge on each capacitor. µC (c) Find the potential difference (in V) on each capacitor. 5.42 pF capacitor 1.18 The potential difference across each of the capacitors in the circuit is given by AV = . Use this relationship and the charge found in part (b) to find the desired values. V 6.00 µF capacitor 1.18 The potential difference across each of the capacitors in the circuit is given by AV = 2. Use this relationship and the charge found in part (b) to find the desired values. V 7.14 pF capacitor V 2.00 uF capacitor V

QUESTION 1 Find the equivalent capacitance of the combination if C₁ = 10 mF, C₂ = 5 mF and C3 = 4 mF. C₂₂ C3 OA. 9.35 mF OB. 8.93 mF OC.2.11 mF OD. 1.82 mF OE. 3.16 mF particles, each with posit

For the system of capacitors shown in the figure below, find the following. (Let C, = 1.00 µF and C2 = 9.00 µF.) 6.00 µF 2.00 µF + 90.0 V (a) the equivalent capacitance of the system 2 Your response differs from the correct answer by more than 10%. Double check your calculations. µF (b) the charge on each capacitor on C1 on C2 on the 6.00 µF capacitor on the 2.00 µF capacitor (c) the potential difference across each capacitor across C, V across C2 V across the 6.00 µF capacitor V across the 2.00 µF capacitor V

A 33.0 µF capacitor is charged with 13.30 V power source, how much charge is stored in that capacitor? Where is the charge stored?

Consider the following. (LetC₁ 12.80 μF and C₂ = 6.80 μF.) 6.00 με C₁₂: + 9.00 V C₁ (a) Find the equivalent capacitance of the capacitors in the figure. μF (b) Find the charge on each capacitor. on the right 12.80 μF capacitor on the left 12.80 μF capacitor on the 6.80 µF capacitor on the 6.00 μF capacitor 9999

3.00 uF 6.00 uF 10. For the system of capacitors shown in Figure, find: (a) the equivalent capacitance of the system, (b) the voltage on each capacitor 2.00 μF 4.00 μF 90.0 V

For the system of capacitors shown in the figure below, find the following. (Let C1 = 4.00 microfarad and C2 = 8.00 microfarad.) c) the potential difference across each capacitor across C1     V across C2      V across the 6.00 µF capacitor      V across the 2.00 µF capacitor      V

Find the equivalent capacitance of the group of capacitors shown in the figure below. (Let C₁ = 4.90 μF, C₂ = 4.50 μF, C3 = 3.10 μF, C₁ = 1.90 μF, C5 = 3.20 μF, C6 = 7.40 μF, C₂ = 6.20 μF.) UF C₂ !! HE + 48.0 V 46

For Problems 4-6 find the equivalent Capacitance, the Potential across Capacitor 3, and the Charge on Capacitor 4 C₁=6F 6.00 volts C₂=3F C₂ = 10 F C₁ = 14 F 4. Ceq= V3 = Q4=

In the circuit shown in (Figure 1), the potential difference across abab is 23.5 VV. Calculate the charge on the 5.00 μF capacitor. The last time I asked this question, the answer was wrong